MATHEMATICS MIDDLE SCHOOL

Which values of p and q would make the value of the following expression equal to 58i? (3 – 7i)(p + qi)i

Answers

Answer 1

Answer:

we are given

$(3-7i)(p+qi)i=58i$

firstly, we will simplify left side

and then we can compare it with right side

so, we can distribute

$(3p+3qi-7pi-7qi^2)i=58i$

$(3p+3qi-7pi+7q)i=58i$

we have i on both sides

so,i will get cancelled

$(3p+3qi-7pi+7q)=58$

$(3p+7q+(3q-7p)i)=58$

we can also write as

$(3p+7q)+(3q-7p)i=58+0*i$

now, we can compare

and we get

$3p+7q=58$

$3q-7p=0$

now, we can solve for p and q

we get

$q=7,\:p=3$ .............Answer

Answer 2

Answer:

Answer:

For short the answer is A. p = 3 , q = 7

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A school held a jump-roping contest. Diego jumped rope for 20 minutes. Jada jumped rope for 15 minutes. What percentage of Diego’s time is that?
Lin jumped rope for 24 minutes. What percentage of Diego’s time is that?
Noah jumped rope for 9 minutes. What percentage of Diego’s time is that?
Diego 20/20 = 1
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Answers

Answer:

Jada 15

Lin 24

Noah 9

Diego 20

Step-by-step explanation:

Hope I helped

How much would $500 invested at 8% interest compounded continuously beworth after 3 years? Round your answer to the nearest cent.
Alt) - Poet
A. $629.86
B. $620.00
C. $641.28
D. $635.61

Answers

Based on the given parameters, the value of the investment after 3 years is $629.86

How to determine the amount in five years?

The given parameters about the compound interest are

Principal Amount, P = $500

Interest Rate, R = 8%

Time, t = 3

Compound interests are different from simple interest, and they are calculated using the following compound interest formula

CI = P(1 + R)^t - P

To calculate the amount, we have:

A = P + CI

So, the equation becomes

A = P + P(1 + R)^t - P

Evaluate the like terms

A = P(1 + R)^t

Substitute the known values in the above equation

A = 500 * (1 + 8%)^3

Express 8% as decimal

A = 500 * (1 + 0.08)^3

Evaluate the sum

A = 500 * (1.08)^3

Evaluate the exponent

A = 500 * 1.259

Evaluate the product

A = 629.86

Hence, the value of the investment after 3 years is $629.86

Read more about compound interest at:

brainly.com/question/24924853

#SPJ1

Answer:

Step-by-step explanation:

A volume of the triangular block is 4 cubic inches, what is the approximate length of y? Round to the nearest tenth of an inch

Answers

Answer:

2.8 inches will be the approximate length of the y.

Step-by-step explanation:

volume = 1/2 x A x C x H = 4 cubic inches

Because the volume of the triangular block is 4 cubic inches.

Formula:

A x C = Base x Height

Answer:

2.8 in

Step-by-step explanation:

The label that wraps around a a can is 4 inches long. How wide is the can?

Answers

1.273 is the answer

bc the label is circumference and the width would be diameter

so circumference divided by pi is diameter

so 4 ÷ 3.14 = 1.273

At an animal shelter, there are 15 dogs, 12 cats, 3 snakes, and 5 parakeets. What percent less parakeets are there than dogs?

Answers

Answer: The required percentage is 28.57%.

Step-by-step explanation: Given that at an animal shelter, there are 15 dogs, 12 cats, 3 snakes, and 5 parakeets.

We are to find the percentage by which parakeets are less than dogs.

From the given information, the number of dogs is

$n_d=15,$

the number of parakeets is

$n_p=5.$

And, the total number of animals is

$n=15+1+3+5=35.$

So, the difference of the number of dogs and parakeets is

$N=n_d-n_p=15-5=10.$

Therefore, the percentage by which parakeets are less than dogs is

$(N)/(n)*100\%=(10)/(35)*100\%=(200)/(7)\%=28.57\%.$

Thus, the required percentage is 28.57%.

There are 35 total animals and 5 parakeets and 15 dogs. 15/35*100 is there percentage of dogs and 5/25*100 is the percentage of parakeets. (15-5)/35*100 is the percentage difference. Simplifying, this equals 28.571%

Write the quadratic equation in standard form:
- 4x² – 13 – 2x = 4x - 2x²
(Urgent!)

Answers

Answer:

$2 {x}^(2) + 6x + 13 = 0$

Step-by-step explanation:

$- 4 {x}^(2) - 13 - 2x = 4x - 2 {x}^(2) \n 4x - 2 {x}^(2) + 4 {x}^(2) + 13 + 2x = 0 \n 4 {x}^(2) - 2 {x}^(2) + 4x + 2x + 13 = 0 \n \purple{ \boxed{ \bold{2 {x}^(2) + 6x + 13 = 0}}} \n is \: the \: standard \: form \:$

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