Adam wraps the top edge of the gift box shown with gold ribbon. The top and bottom edges of the box are square. If Adam has 24 1/4 cm of gold ribbon, does he have enough to decorate the top of the box?

Answers

Answer 1

Answer:

The perimeter of a shape is the sum of the visible lengths of the shape. Adam does not have enough ribbon to decorate the top of the box.

I've added the gift box, as an attachment.

From the attached image, we have:

$Volume = 296$

$Height = 8$

Next, we calculate the length and the width of the box using:

$Volume = Length * Width * Height$

The top and bottom edges are square. This means that:

$Length = Width$

So, we have:

$Volume = Length * Length * Height$

Substitute known values

$296 = Length * Length * 8$

$296 = Length^2 * 8$

Divide both sides by 8

$37 = Length^2$

Take square roots of both sides

$6.1 = Length$

So, we have:

$Length = Width = 6.1$

Calculate perimeter (P) of the top edge of the box

$P =2 * (Length + Width)$

$P =2 * (6.1 + 6.1)$

$P =2 * (12.2)$

$P =24.4$

This means that Adam needs 24.4 cm of gold ribbon to wrap the top edge

By comparison:

$24.4 > 24\frac 14$

$24.4 > 24.25$

24.4 cm is greater than the length of Adam's gold ribbon (24.25).

Hence, we can conclude that he does not have enough ribbon to decorate the top of the box.

Learn more about perimeters at:

brainly.com/question/6465134

Answer 2

Answer:

No , he does not have enough

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Answers

Question # 1 Solution

Answer:

$(h-f)(-8)=-229$

Step-by-step Solution:

Given

$h(r)=-4r^(2)+4$

$f(r)=2r-7$

$(h-f)(r)=h(r)-f(r)$

$(h-f)(r)=-4r^(2)+4-(2r-7)$

$(h-f)(r)=-4r^(2)+4-2r+7)$

We have to find $(h-f)(-8)$

So,

$(h-f)(-8)=-4(-8)^(2)+4-2(-8)+7)$

$(h-f)(-8)=-4(64)+4+16+7$

$(h-f)(-8)=-256+4+16+7$

$(h-f)(-8)=-229$

∴ $(h-f)(-8)=-229$

Question # 2 Solution

Answer:

∴ $(f.p)(9)=38979$

Step-by-step Solution:

Given

$f(s)=7s-2$

$p(s)=s^(3)-10s$

$(f.p)(s)=f(s).p(s)$

$(f.p)(s)=(7s-2)(s^(3)-10s)$

$(f.p)(s)=7s^4-2s^3-70s^2+20s$

We have to find $(f.p)(9)$

So,

$(f.p)(9)=7\left(9\right)^4-2\left(9\right)^3-70\left(9\right)^2+20\left(9\right)$

$(f.p)(9)=7\cdot \:9^4-2\cdot \:9^3-70\cdot \:9^2+20\cdot \:9$

$(f.p)(9)=9^4\cdot \:7-9^3\cdot \:2-9^2\cdot \:70+180$

$(f.p)(9)=45927-1458-5670+180$

$(f.p)(9)=38979$

∴ $(f.p)(9)=38979$

Question # 3 Solution

Answer:

$((f)/(p))(r)=(11r+8)/(r\left(r^2+6\right))$

Step-by-step Solution:

Given

$p(r)=r^(3)+6r$

$f(r)=11r+8$

We have to find $((f)/(p))(r)$

Using the formula

$((f)/(p))(r)=(f(r))/(p(r))$

$p(r)=r^(3)+6r$

$f(r)=11r+8$

$((f)/(p))(r)=(11r+8)/(r^(3)+6r)$

$((f)/(p))(r)=(11r+8)/(r\left(r^2+6\right))$

∴ $((f)/(p))(r)=(11r+8)/(r\left(r^2+6\right))$

Question # 4 Solution

Answer:

$(h-p)(k)=5k^2-3-k^3-8k$

Step-by-step Solution:

Given

$h(k)=5k^(2)-3$

$p(k)=k^(3)+8k$

We have to find $(h-p)(k)$

Using the formula

$(h-p)(k)=h(k)-p(k)$

$h(k)=5k^(2)-3$

$p(k)=k^(3)+8k$

$(h-p)(k)=5k^(2)-3-(k^(3)+8k)$

$(h-p)(k)=5k^2-3-k^3-8k$

∴ $(h-p)(k)=5k^2-3-k^3-8k$

Question # 5 Solution

Answer:

$((p)/(g))(11)=(1287)/(155)$

Step-by-step Solution:

Given

$p(b)=b^(3)-4b$

$g(b)=b^(2)+4b-10$

We have to find $((p)/(g))(11)$

$((p)/(g))(b)=(p(b))/(g(b))$

$((p)/(g))(b)=(b^(3)-4b)/(b^(2)+4b-10)$

$((p)/(g))(11)=(11^(3)-4(11))/(11^(2)+4(11)-10)$

$((p)/(g))(11)=(1287)/(155)$

∴ $((p)/(g))(11)=(1287)/(155)$

Question # 6 Solution

Answer:

$(f+g)(x)=x^2+20x-18$

Step-by-step Solution:

Given

$g(x)=x^(2)+11x-7$

$f(x)=9x-11$

We have to find $(f+g)(x)$

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=9x-11+(x^(2)+11x-7)$

$(f+g)(x)=9x-11+x^(2)+11x-7$

$(f+g)(x)=x^2+20x-18$

∴ $(f+g)(x)=x^2+20x-18$

Question # 7 Solution

Answer:

$h(10)+g(10)=-983$

Step-by-step Solution:

Given

$h(w)=-11w^(2)-7$

$g(w)=w^(2)+3w-6$

We have to find $h(10)+g(10)$

So,

$h(10)=-11(10)^(2)-7$

$h(10)=-1107$ .....[1]

and

$g(10)=10^(2)+3(10)-6$

$g(10)=124$ .....[2]

Adding Equation [1] and Equation [2]

$h(10)+g(10)=-1107+124$

$h(10)+g(10)=-983$

∴ $h(10)+g(10)=-983$

Question # 8 Solution

Answer:

$(f+g)(-3)=-6$

Step-by-step Solution:

Given

$g(b)=b^(2)+9b+10$

$f(b)=3b+11$

We have to find $(f+g)(-3)$

$(f+g)(b)=f(b)+g(b)$

$(f+g)(b)=3b+11+b^(2)+9b+10$

$(f+g)(-3)=3(-3)+11+(-3)^(2)+9(-3)+10$

$(f+g)(-3)=-6$

∴ $(f+g)(-3)=-6$

Question # 9 Solution

Answer:

$(f.h)(k)=33k^3+22k-12k^2-8$

Step-by-step Solution:

Given

$f(k)=-11k+4$

$h(k)=-3k^(2)-2$

We have to find $(f.h)(k)$

$(f.h)(k)=f(k).h(k)$

So,

$(f.h)(k)=(-11k+4).(-3k^(2)-2)$

$\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$

∵ FOIL means (First, Outer, Inner, Last)

$(f.h)(k)=\left(-11k\right)\left(-3k^2\right)+\left(-11k\right)\left(-2\right)+4\left(-3k^2\right)+4\left(-2\right)$

$(f.h)(k)=33k^3+22k-12k^2-8$

∴ $(f.h)(k)=33k^3+22k-12k^2-8$

Question # 10 Solution

Answer:

$p(-8)-f(-8)=-581$

Step-by-step Solution:

Given

$p(s)=s^(3)+6s$

$f(s)=-2s+5$

We have to find $p(-8)-f(-8)$

So,

$p(-8)=(-8)^(3)+6(-8)$

$p(-8)=-560.....[1]$

and

$f(-8)=-2(-8)+5$

$f(-8)=21.....[2]$

Subtracting Equation [2] from Equation [1]

$p(-8)-f(-8)=-560-21$

$p(-8)-f(-8)=-581$

∴ $p(-8)-f(-8)=-581$

Keywords: function operation

Learn more about function operations from brainly.com/question/3725682

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Answer:

-2229

Step-by-step explanation:

Here is a list of numbers. 17 21 14 17 12 15 what is the mean

Answers

Answer:

Step-by-step explanation:

you add all of them up and then divide by how many numbers you have total.

17+21+14+17+12+15=96

96/6

=16

Answer:

Step-by-step explanation:

17+21+14+17+12+15=96

96/6= 16

6 is the number of numbers in that list of numbers

add them together and divide it by how many numbers are there.

in this case it is 6 . therefore the answer is 16

What is the equation of the line that has a slope of 3 and goes through the point (-3,-5)?A.
y = 3x + 4
B.
c.
D.
y= 3x - 14
y= 3x - 4
y=3x + 12

Answers

Answer:

A: y = 3x + 4

Step-by-step explanation:

A slope of 3 is given, so the co-efficient of x must be three

If you are going through point (-3, -5), then you must have a starting point.

Adding 3 to the y coordinate for every x value gives us 4.

This means that the equation must be adding 4 to x.

So, the answer is y = 3x + 4, or A.

to make a lemon-lime drink, Mac mixed 4 liters of lemonade with 2 liters of limeade. How much lemon-lime drink did Mac make? "

Answers

Mac made 6 liters of lemon-lime drink by mixing 4 liters of lemonade with 2 liters of limeade.

What is an expression?

An expression is a combination of numbers, variables, and operators (such as addition, subtraction, multiplication, and division) that represents a mathematical or logical calculation. It can include constants, variables, and functions that can be evaluated to produce a value.

To find out how much lemon-lime drink Mac made, we need to add the volumes of the lemonade and limeade together:

4 liters (lemonade) + 2 liters (limeade) = 6 liters (lemon-lime drink)

Therefore, Mac made 6 liters of lemon-lime drink by mixing 4 liters of lemonade with 2 liters of limeade.

To know more about an expression follow

brainly.com/question/30297714

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Answer: The answer would be 4

Step-by-step explanation:

If you add 4+2 then you are Correct, 4+2=6 that is the right answer

What are the coordinates of point H?

Answers

Real simple...

let's go step-by-step...

you know..that to find the coordinates of a point..you first go to the

x-axis...

move over..and find where point H is at..it's at -1.5..

Then..move up to find where it's located on the

y-axis..

move up and see it's at 3

Thus, the coordinates..(-1.5,3)

(x,y)
x means how many units right from the center the points is (if it is to the left of center, say it is negative units)

y means how many units up from center the point is (if it is under center, say it is negative)

it is to th eleft and above center
(-,+)
count how far to the right
-1.5 units to right

how far up
3 unit sup
(-1.5,3)

What is the area of the figure? Base:12 m Hight:5 m width: 2 m

Answers

The area is base times height so it would be 60m squared. But if you meant volume, which is base times height times width, then it would be 120 m cubed.

120 12x5=60 60x2=120

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