MATHEMATICS HIGH SCHOOL

The loudness, L , of a sound (measured in decibels, dB) is inversely proportional to the square of the distance, d , from the source of the sound. A person 14 feet from a jetski, it is 75 decibels loud.

How loud is the jetski when the person is 45 feet away?

Answers

Answer 1
Answer:

Answer

7.2593 decibels


Explanation

L ∝ 1/d² Inserting the constant of variation,

L = k/d²

k = Ld²

  = 75 × 14²

  = 14,700

When d = 45 feet;

L = 14,700/45²

  = 14,700/2,025

 = 7.2593 decibels
Answer 2
Answer:

When the person is 45 feet away from the jetski, it is approximately 24.07 decibels loud.

How to determine How loud is the jetski when the person is 45 feet away

We can use the inverse square law to find how loud the jetski is when the person is 45 feet away. The inverse square law states that the loudness (\(L\)) is inversely proportional to the square of the distance (\(d\)):

\[L = k \cdot (1)/(d^2)\]

We are given that when the person is 14 feet away,\(L = 75\). We can use this information to find the value of \(k\):

\[75 = k \cdot (1)/(14^2)\]

Now, solve for \(k\):

\[k = 75 \cdot 14^2\]

Now that we have the value of \(k\), we can use it to find the loudness (\(L\)) when the person is 45 feet away:

\[L = k \cdot (1)/(45^2)\]

Plug in the value of \(k\) we found:

\[L = 75 \cdot 14^2 \cdot (1)/(45^2)\]

Calculate this expression to find the loudness (\(L\)) when the person is 45 feet away:

\[L \approx 24.07 \text{ dB}\]

So, when the person is 45 feet away from the jetski, it is approximately 24.07 decibels loud.

Learn more about inverse square law at brainly.com/question/30562749

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HELP!!

Write five different integers that have a mean of -10.

Answers

Answer:
1,2,3,4, -60

Explanation:
The sum of the values = -10 • 5 = -50

1+2+3+4+ (-60) = -50

So
1,2,3,4, -60 are your integers

Which measurement is not equivalent to the others?2 quart
8 cups
72 fl. oz.
4 pints

Answers

If you would like to know which measurement is not equivalent to the others, you can calculate this using the following steps:

1 quart = 4 cups = 2 pints = 32 fl. oz.

2 quarts = 2 * 4 cups = 8 cups
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Select the proper placement for parentheses to speed up the addition for the expression 4 + 6 + 5 A. (5 + 6) + 4   B. (4 + 6) + 5   C. 4 + (6 + 5)   D. (5 + 4) + 6

Answers

im guessing that by making 10 it will speed up the addition process so it should be 
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Can someone help me and let me know if my answer is correct?A large emerald with a mass of 764.3 grams was recently discovered in a mine. If the density of the emerald is 2.76grams over centimeters cubed, what is the volume? Round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point.

276.92

Answers

The answer is 276.92

The density (D) of is quotient of mass (m) and volume (V):
D = (m)/(V)

It is given:
m = 764.3 g
D = 2.76 g/cm³
V = ?

Since:
D = (m)/(V)
⇒ V= (m)/(D)= (764.3g)/(2.76g/cm^(3) ) = 276.92 cm ^(3)

Therefore, the volume of the emerald is 276.92 cm² and your answer is correct.

Answer:

276.92 cubic cm.

Step-by-step explanation:

Given :

A large emerald with a mass of 764.3 grams was recently discovered in a mine.

The density of the emerald is 2.76gm/cm^3

To Find: what is the volume?

Solution:

Density =2.76gm/cm^3

Mass = 764.3 grams

Volume=(Mass)/(Density)

Volume=(764.3)/(2.76)

Volume=276.92

Hence the volume of large emerald is 276.92 cubic cm.

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Answers

1325 \geq 26x +270

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So the budget is 1,325 and you are trying to find a value to fit into that price range which means it has to be less than or equal to 1,325.  To do that, you already know that the conference room will cost 270 no matter what so you have to add that to the the amount for lunch which means you are subtracting it from the total cost of the budget.
1055 \geq 26x

Then you divide what's left of the budget by the number of people.
(1055)/(26) \geq x

That leaves you with x which is the amount you can spend on lunch per person.
I finished it off for you and got 40.58 \geq x which is the same as x \leq 40.58

That means you can spend less than or equal to in other words at most $40.58 on lunch per person.

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