9x^2+3x^3
Here, we are required to factorise fully 9x² + 3x³
To factorise the expression 9x² + 3x² fully; we first need to write out factors of 9x² and 3x³ respectively. Thus;
Since 3x² is a common factor for 9x² and 3x³,
3x² can be factored out so that we have the result of the factorization to be;
3x²(3+x)
as "3" and "x" are the remaining factors of 9x² and 3x³ respectively.
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Answer:
3x^2(3+x)
Step-by-step explanation:
9x^2+3x^3
3(3x^2+x^3)
3x^2(3+x)
Answer:
y = 2x + 11
Step-by-step explanation:
Slope-intercept form (y=mx+b) of linear equations highlights the slope (m) and the y-intercept (b) of a line.
Slope = m = rise/run = (y2-y1)/(x2-x1) = (15-21)/(2-5) = -6/-3 = 2
substitute 2 back into the equation.
y = mx + b
y = 2x + b
use one of the provided points to solve for b.
y = 2x + b
15 = 2(2) + b
15 = 4 + b
11 = b
y = 2x + 11
Answer:
The answer is 32.
Step-by-step explanation:
Remember that order of operation is very important in this problem.
Substitute x for 3 and y for 2 in the equation.
When solving the first term, we must note that we have to square the 3 first before we multiply it by 4. So, 4(3)^2 is basically 36. To simplify the second term you just have to do 2*2, which is 4. 36-4=32, which is the answer.
Answer:
The broker's commission was rupees 8,250
Step-by-step explanation:
Selling price of property = rupees 450,000
The sale price is higher than rupees 300,000
Commission for rupees 300,000 = 2% × rupees 300,000 = rupees 6,000
Remaining amount = rupees 450,000 - rupees 300,000 = rupees 150,000
Commission for the remaining amount = 1.5% × rupees 150,000 = 0.015 × rupees 150,000 = rupees 2,250
Total commission = rupees 6,000 + rupees 2,250 = rupees 8,250