Help me please
!!!!!!!!!!!!!!!
Help me please !!!!!!!!!!!!!!! - 1

Answers

Answer 1
Answer:

S is in negative territory. So it is going to take you a distance to get to 0 and move further right to T.

You can do this without a formula just by adding 2 to get to zero and then 14 more to get to T. The distance between S and T is 14 + 2 = 16.

Now we should develop some kind of formula for these questions. When one point is on one side of zero on the number line and the other point is on the other side of zero then the formula for distance is

distance (as a formula for this question) = abs(S) + abs(T)

Distance = abs(-2) + abs(14) = 2 + 14 = 16

When both point are on the same side of zero then the formula becomes

Distance= abs(abs(S) - abs(T) )

For example if S = -2 and T = - 9

Then the distance = abs( abs(-2) - abs(-9) ) = abs(2 - 9) = abs(-7) = 7

If you have not taken abs value, then just take the answer that I have given above.

Answer 2
Answer:

The distance between S and T:

|-2| + 14

= 2 + 14

= 16

Answer

16 units


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Ty is right inches taller than his brother Reece if ty is 42 inches tall how tall is Reece. Write an equation using a variable r?
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Match the polygons formed by the sets of points with their perimeters ( rounded to the nearest hundredth). Please Help me I don't understand this question. Thank youA( 1, 1), B(6,13), C(8,13), D(16,-2) E(1, -2 )
38 units
K(4,2), L(8,2), M(12,5), N(6,5), O(4,4)
50 units
F(14,-10), G(16, -10), H(19,-6), I (14,-2), J(11,-6)
25.4 units
P(7,2), Q (12,2), R(12,6), S(7,10), T(4,6)
19.24 units
U(4, -1), V(12, -1), W(20,-7), X(8, -7), Y(4,-4)

Answers

Answer with explanation:

→→Using the Distance formula,\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 finding the distance between two points that is between two vertices

The Points which are vertices of Polygons are

1.→ A( 1, 1), B(6,13), C(8,13), D(16,-2) E(1, -2 )

AB=√((6-1)^2+(13-1)^2)\n\nAB=√(5^2+12^2)\n\n AB=√(25+144)\n\n AB=√(169)\n\n AB=13

BC=√((8-6)^2+(13-13)^2)\n\n BC=√(2^2)\n\n BC=2

CD=√((16-8)^2+(-2-13)^2)\n\n CD=√(8^2+15^2)\n\nCD=√(64+225)\n\nCD=√(289)\n\nCD=17\n\nDE=√((16-1)^2+(-2+2)^2)\n\nDE=√(15^2)\n\nDE=15 \n\nAE=√((1-1)^2+(-2-1)^2)\n\n AE=√(3^2)\n\n AE=3

→→AB+BC+CD+DE+EA= 13+2+17+15+3

         =50 units

2. K(4,2), L(8,2), M(12,5), N(6,5), O(4,4)

KL=√((8-4)^2+(2-2)^2)=√(4^2)=4\n\n LM=√((8-12)^2+(2-5)^2)=√(4^2+3^2)=√(5^2)=5\n\nMN=√((12-6)^2+(5-5)^2)=√(6^2)=6\n\nNO=√((6-4)^2+(5-4)^2)=√(2^2+1^2)=√(5)\n\nKO=√((4-4)^2+(4-2)^2)=√(2^2)=2

KL+LM+MN+NO+OK=4+5+6+√5+2

                                 =17+2.24

                                 = 19.24 units

3. F(14,-10), G(16, -10), H(19,-6), I (14,-2), J(11,-6)

FG=√((16-14)^2+(-10+10)^2)=√(2^2)=2\n\n GH=√((19-16)^2+(-6+10)^2)=√(4^2+3^2)=√(5^2)=5\n\nHI=√((19-14)^2+(-6+2)^2)=√(5^2+4^2)=√(25+16)=√(41)\n\nIJ=√((14-11)^2+(-2+6)^2)=√(3^2+4^2)=√(5^2)=5\n\nJF=√((14-11)^2+(-10+6)^2)=√(3^2+4^2)=√(5^2)=5

→FG+GH+HI+IJ+JF=2+5+√41+5+5=19+6.40=25.40

4.→ P(7,2), Q (12,2), R(12,6), S(7,10), T(4,6)

 PQ=√((12-7)^2+(2-2)^2)=√(5^2)=5\n\n QR=√((12-12)^2+(-6+2)^2)=√(4^2+0^2)=√(4^2)=4\n\nRS=√((12-7)^2+(-6+10)^2)=√(5^2+4^2)=√(25+16)=√(41)\n\nST=√((7-4)^2+(-10+6)^2)=√(3^2+4^2)=√(5^2)=5\n\nPT=√((7-4)^2+(-2+6)^2)=√(3^2+4^2)=√(5^2)=5

PQ+QR+RS+ST+TP=5+4+√41+5+5

                              =19+6.40

                              = 25.40 units

5.→U(4, -1), V(12, -1), W(20,-7), X(8, -7), Y(4,-4)

UV=√((12-4)^2+(-1+1)^2)=√(8^2)=8\n\n VW=√((20-12)^2+(-7+1)^2)=√(8^2+6^2)=√(64+36)=√(100)=10\n\nWX=√((20-8)^2+(-7+7)^2)=√(12^2+0^2)=12\n\nXY=√((8-4)^2+(-7+4)^2)=√(3^2+4^2)=√(5^2)=5\n\nYU=√((4-4)^2+(-4+1)^2)=√(3^2+0^2)=√(3^2)=3

UV +V W+W X+XY+YU

      = 8+10+12+5+3

       =38 units

38 units-U(4, -1), V(12, -1), W(20,-7), X(8, -7), Y(4,-4)


25.4 units-P(7,2), Q (12,2), R(12,6), S(7,10), T(4,6)


50 units-A( 1, 1), B(6,13), C(8,13), D(16,-2) E(1, -2 )


19.24 units-K(4,2), L(8,2), M(12,5), N(6,5), O(4,4)

Find the difference.(5x2 + 2x + 11) - (7 + 4x - 2x2)
A.
3x2 + 6x + 4
B.
9 - 2x - 2x2
C.
3x2 - 2x + 4
D.
7x2 - 2x + 4

Answers

Answer:

D

Step-by-step explanation:

Answer:

D.)   9 − 2x − 2x2

The following parallelogram is not drawn to scale.Find the unknown angle:
142⁰
a
za =

Answers

The twο adjacent angles in the parallelοgram are 142 degrees and 38 degrees, and the οppοsite angles are alsο equal tο 142 degrees and 38 degrees.

What are the supplementary angles?

Supplementary angles are thοse angles that sum up tο 180 degrees. Fοr example, angle 130° and angle 50° are supplementary angles because the sum οf 130° and 50° is equal tο 180°.

In a parallelοgram, οppοsite angles are equal and supplementary, which means they add up tο 180 degrees. Therefοre, the οppοsite angle tο the given angle οf 142 degrees is alsο supplementary tο it and equal tο0

180 - 142 = 38 degrees.

Since οppοsite sides οf a parallelοgram are parallel and cοngruent, the adjacent angles are alsο cοngruent. Therefοre, the οther angle adjacent tο the given angle οf 142 degrees is alsο equal tο 142 degrees.

Hence, the twο adjacent angles in the parallelοgram are 142 degrees and 38 degrees, and the οppοsite angles are alsο equal tο 142 degrees and 38 degrees.

To learn more about supplementary angles visit:

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Complete question:

On discovering that her family had a 70% risk of heart attack, Erin took a treadmill test to check her own potential of having a heart attack. The doctors told her that the reliability of the stress test is 67%. The test predicted that Erin will not have a heart attack. What is the probability after the test was taken that she will have a heart attack?0.4051
0.5010
0.4653
0.6632

Answers

The test predicted that Erin will not have a heart attack. The probability after the test was taken that she will have a heart attack is 0.4653. the rest of teh choices do not answer the question above.

Answer:

THERE CORRECT JUST FOR RESHORENCE

Step-by-step explanation:

PLEASE HELP!!!!!!solve for the equations :
- 3y + 7 + 3(y-1) = 2(2y+6)

- (x-5)(x+4) = (x+7)(x-6)

- 2(x+1)2(x-2)2 = x(x-3)

Answers

-3y + 7 + 3(y - 1) = 2(2y + 6)
-3y + 7 + 3y - 3 = 4y + 12
4y = 4 - 12 = -8
y = -8/4 = -2.

-(x - 5)(x + 4) = (x + 7)(x - 6)
-(x^2 + 4x - 5x - 20) = x^2 - 6x + 7x - 42
-x^2 + x + 20 = x^2 + x - 42
2x^2 = 62
x^2 = 62/2 = 31
x=\pm√(31)
1.y=-2
2. x1,2=+-5.56
3.x1=16.13 , x2=-0.85

25. Write an expression to represent the area of the shaded region in simplest form.5x + 2
x + 7
3x - 1

Answers

Final answer:

The expression to represent the area of the shaded region is (5x + 2)(x + 7) - (3x - 1)(x + 7). Simplifying the expression gives us 2x^2 + 42x + 7.

Explanation:

To find the area of the shaded region, we need to subtract the area of the smaller rectangle from the area of the larger rectangle. The larger rectangle has a length of (5x + 2) and a width of (x + 7), while the smaller rectangle has a length of (3x - 1) and a width of (x + 7). Therefore, the expression to represent the area of the shaded region is:

(5x + 2)(x + 7) - (3x - 1)(x + 7)

To simplify this expression, we can use the distributive property. First, we simplify the expression in the parentheses:

(5x + 2)(x + 7) - (3x - 1)(x + 7)

(5x^2 + 35x + 2x + 14) - (3x^2 - 7x - x + 7)

Next, we distribute the negative sign:

5x^2 + 35x + 2x + 14 - 3x^2 + 7x + x - 7

Finally, we combine like terms:

2x^2 + 42x + 7

Learn more about Simplifying expressions here:

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Answer:

Step-by-step explanation:

To determine what the area of the shaded region is, simply find the area of the large rectangle and subtract the product from the smaller one.

Since they are polynomials. Multiply one binomial to the other and first obtain the product, before subtracting the product of the smaller rectangle.

(5x + 2)(3x - 1) - (x)(x + 7)

15x^2 - 5x + 6x - 2 - x^2 - 7

14x^2 + x - 9.

I believe this would be the solution in standard form.