A company has two electric motors that consume varying amounts of power. The power consumed by each motor is a function of the time (t in minutes) for which it runs. The cost of power (in $) to run one motor is given by the function `C_a(t) = t^2 - 2t + 5`. The cost of running the second motor is given by `C_b(t) = 3t + 2`. Which function gives the total cost of running both motors?

Answers

Answer 1

Answer:

try to do it as a simple multiplication problem

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Find the quadratic equation whose roots are 3+- i / 2

Answers

(x - root#1) times (x - root#2) = 0 . . . . . This is how to BUILD the quadratic equation.

All the rest is just multiplying out that first line:

(x- (3+i/2)) times (x - (3-i/2)) = 0

x² -x(3-i/2) -x(3+i/2) + (3+i/2)(3-i/2) = 0

x² -3x + ix/2 -3x - ix/2 + 9 -3i/2 + 3i/2 = 0

x² -6x +9 = 0 There it is. That's your quadratic equation.

What is nine more than a number y, if that number is 4?
13
9
4
7

Answers

Answer:

$\huge\boxed{13}$

Step-by-step explanation:

The unknown number is y

Given condition is:

=> y + 9

Given that y = 4

=> 4 + 9

=> 13

$\rule [225]{225}{2}$

Hope this helped!

~AnonymousHelper1807

What is the factored form of 5x+x^2=0

Answers

$5x+x^2=0\n \nx(5+x)=0\n \nx=0 \ \vee \ 5+x=0 \n\n x=0 \ \vee \ x=-5$

If i have all the angles and one side can i find the other sides

Answers

Sure, that's what solving triangles is. Trigonometry has a short menu. Basically we choose between three formulas: Law of Sines, Law of Cosines, Sum of Triangle Angles

The Law of Sines has two sides and two opposite angles; given any three we can solve for the fourth.

The Law of Cosines has three sides and one angle; again given any three we solve for the remaining one.

The Sum of Triangle Angles says all three angles add to 180 degrees, so given two we can find the third.

Here we have all the angles and one side, that's Law of Sines to get the remaining sides.

Solve 4/(x + 1) - 1/x = 1 over the real numbers.

Answers

$( 4)/(x + 1) - (1)/(x) = 1 \n \nx+1\neq 0 \ \ \ and \ \ \ x\neq 0 \n \nx\neq -1 \ \ \ and \ \ \ x\neq 0 \n \nD=R\setminus \left \{ -1,0 \right \}$

$( 4x- (x+1))/(x(x + 1)) = 1 \n \n( 4x- x-1 )/(x^2+ x)=1 \n \n( 3x -1 )/(x^2 + x) = 1 \n \n3x-1=x^2+x\n \n x^2+x-3x+1=0$

$x^2-2x+1=0 \n \n (x-1)^2=0 \n \nx-1=0 \n \nx=1$

Ok sorry I guessed this one but it was x = 1
4/(1+1) - 1/1 = 1
2 - 1 = 1
And it's right :)

What is the value of 8P4?

Answers

8P4 is a permutation;

P(n,r) ; nPr = n!/(n-r)!

8P4 = 8!/(8-4)! = 40,320 / 4! = 40,320 / 24 = 1,680

The value of 8P4 is 1,680

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