F the solution described in the introduction is cooled to 0 ∘c, what mass of kno3 should crystallize?

Answers

Answer 1

Answer:

Assuming the other part of the question is;

A solid mixture consists of 44.2g of KNO3 (potassium nitrate) and 7.8g of K2SO4 (potassium sulfate). The mixture is added to 130. g of water. (Assume KNO3 has a solubility of 14 g solute/ 100 g water)

Answer;

26 g

Solution;

-X g of KNO3/ 130 g water= 14 g of KNO3/ 100 g water

X= 18.2 g (this is the amount of solute that dissolves at 0 degrees C in 130 g water).

if you have 44.3g of KNO3 in 130 g of water at 0 degrees celsius and only 18.2 can dissolve then

44.2g - 18.2g = 26 g left undisolved which gives you the amount that would crystallize

Answer 2

Answer:

KNO3 of 10g will undergo crystallization at 0 °

Because the heavier the KNO3 mass will require a higher temperature in the dissolution process.

Further explanation

Potassium nitrate is a nitrate salt compound from potassium with the molecular formula KNO3. Potassium nitrate salt can be made by reacting potassium chloride with sodium nitrate. If the saturated solution each of the solution is mixed with each other, then it will form sodium chloride salt because NaCl in water is small, the salt will settle. By cooling the filtered filtrate KNO3 will undergo crystallization

This compound decomposes with oxygen evolution at 500 ° C according to the reaction equation:

2 NaNO3 (s) -> 2NaNO 2 (s) + O2 (g)

Crystallization is separation by forming crystals so that the mixture can be separated. A gaseous or liquid substance can cool or condense and form crystals because it undergoes a crystallization process. Crystals will also form from a solution that will be saturated with a certain solvent. The more the number of crystals, the better, because the less likely to be polluted by dirt.

Potassium Nitrate has a physical white powder that is easily soluble in water and odorless. Meanwhile, to analyze the structure and characteristics of Potassium Nitrate MM2 data processing is used in the Chemoffice 15.0 application. This data processing is used to determine the shape of compounds, types of bonds in molecular movement compounds and other parts that can not be observed directly by the eye without the aid of tools. And for the form of compounds in 2 dimensions and 3 dimensions used Chemdraw 15.0 and Chem3D 15.0 applications

Learn more

Potassium nitrate brainly.com/question/10847775

Crystallization brainly.com/question/2575925

Details

Grade: High School

Subject: Chemistry

Keyword: kno3, nitrate, crystallization

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Hi i need hel does any one know what P3N2 means ??? .-.

Answers

P=phosphorus
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P3N2 is triphosphorus dinitrogen (a covalent compound)

if you have 3.50 moles of hydrogen and 5.00moles of nitrogen to produce ammonia, witch element is the reactant in excess? 3H2+N2=2NH3

Answers

Given 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, nitrogen is the excess reactant.

What is the excess reactant?

The excess reactant is the reactant in a chemical reaction with a greater amount than necessary to react completely with the limiting reactant.

Step 1: Write the balanced equation.

3 H₂ + N₂ ⇒ 2 NH₃

Step 2: Establish the theoretical ratio.

The theoretical ratio (TR) of H₂ to N₂ is 3:1.

Step 3: Establish the experimental ratio.

The experimental ratio (ER) of H₂ to N₂ is 3.50:5.00 = 0.70:1.

Step 4: Determine the excess reactant.

Comparing TR and ER, we can realize that there is not enough hydrogen to react with the nitrogen. Thus, nitrogen is the excess reactant.

Given 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, nitrogen is the excess reactant.

Learn more about excess reactant here: brainly.com/question/17199947

Answer : The $N_2$ element is the reactant in excess.

Solution : Given,

Moles of $N_2$ = 5 moles

Moles of $H_2$ = 3.50 moles

The balanced chemical reaction is,

$3H_2(g)+N_2(g)\rightarrow 2NH_3(g)$

From the balanced reaction we conclude that

As, 3 moles of $H_2$ react with 1 mole of $N_2$

So, 3.5 moles of $H_2$ react with $(3.5)/(3)=1.16$ moles of $N_2$

The excess of $N_2$ = 5 - 1.16 = 3.84 moles

That means in the given balanced reaction, $H_2$ is a limiting reagent because it limits the formation of products and $N_2$ is an excess reagent.

Hence, the $N_2$ element is the reactant in excess.

A group of students were discussing the lonization energies of Selenium and Flourine. Which student is correct for the reason why their element has the highest lonization energy? O A Student C says F because the larger the atom, the stronger the attraction between protons and valence electrons. The stronger the attraction the more energy is needed to remove a valence electron. B. Student B says Se because the smaller the atom, the stronger the attraction between protons and valence electrons. The stronger the attraction, the more energy is needed to remove a valence electron. C. Student D says F because the smaller the atom, the stronger the attraction between protons and valence electrons. The stronger the attraction, the more energy is needed to remove a valence electron. OD. Student A says Se because the larger the atom, the stronger the attraction between protons and valence electrons. The stronger the attraction the more energy is needed to remove a valence electron.

Answers

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The stronger the attraction, the more energy is needed to remove a valence electron.

Ionization energy refers to the energy required to remove an electron from an atom. Smaller atoms have a stronger attraction between the positively charged protons in the nucleus and the negatively charged electrons in the outermost energy level. As a result, it takes more energy to remove an electron from a smaller atom like fluorine. This is because the electrons are held more tightly due to the stronger attraction.

So, the reasoning provided by Student D correctly explains why Fluorine has the highest ionization energy among Selenium (Se) and Fluorine (F).

Learn more about ionization energy from the link given below.

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I think the Answer is C because Flourine is stronger in electron attraction and is smaller so it has a stronger electronic pull. Hope this helps :)

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Answers

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Answers

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Answer: the beaker 3

Explanation: that what it said on usatestprep

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