Evaluate 2b^2 − 4a + 4a^2 for a = 3 and b = −8.
Answers
(2*(-8)^2)-(4*3)+(4*3^2)
128-12+36
152
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b.153
c.154
d.155
Answers
Answer: Option 'B' is correct.
Step-by-step explanation:
Since we have given that
Number of games she bowl = 4
Score of her in first three games are
149, 162, 152.
Her average score = 154
Let the score in her fourth game be 'x'.
As we know the formula for "Average ":
Hence, Her score in fourth game is 153.
Therefore, Option 'B' is correct.
149+162+152+X=616
X=616-149-162-152=616-314-149=302-149=153
She needs a score of 153.
Answers
Answer:
3.2
Step-by-step explanation:
9.6 divided by 3 is 3.2
from 4x 2 - 4x + 3.
Answers
Subtracting the polynomials, 2x² - 6x - 4 from 4x² - 4x + 3 will give 2x² + 2x + 7
How to subtract polynomials?
Polynomials can have constants, variables and exponents, but never division by a variable.
Let's do the arithmetic of the polynomial.
4x² - 4x + 3 - (2x² - 6x - 4)
Therefore, let's open the bracket with the operator
4x² - 4x + 3 - 2x² + 6x + 4
let's combine the like terms
4x² - 2x²- 4x + 6x + 3 + 4
Therefore,
2x² + 2x + 7
learn more on polynomial here: brainly.com/question/4216386
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(4x^2-4x+3)-(2x^2-6x-4)
4x^2-4x+3-2x^2+6x+4
4x^2-2x^2-4x+6x+3+4=
2x^2+2x+7
4 = 0.25(w-4.3)
Answers
W=20.3
solve what's in the parenthesis, move the terms, calculate, then divide both sides.
Answer:
20.3
Step-by-step explanation:
I did it and it was right on khan
Answers
Answer: p = 120 degrees
Step-by-step explanation:
Figure a shows a pentagon. The sum of interior angles in a pentagon is equal to 540 degrees.
1. Subtract the known numerical angle
540 - 60 = 480
All of the remaining angles (represented by the variable p) are equal to one another. Therefore, we can use the expression 4p = 480 to find the value of p.
2. Evaluate the equation to find the value of p.
4p = 480
p = 120
B. 90
C. 45
D. 60
Answers
Answer:
D. 60°
Step-by-step explanation:
A regular hexagon has 6 equal sides and 6 equal angles.
To rotate the Octagon onto itself, we have to rotate each of those sides to an adjacent side. This happens when the angle of turn is th of a full-circle turn.
A circle has and
A 60° rotation clockwise or counterclockwise puts each of the edges over the position where an adjacent edge was located.