I need help with part a and park b pleasee!
I need help with part a and park b pleasee! - 1

Answers

Answer 1
Answer:

Part A: First plot the points. Then you have to find the midpoint of AB.

Midpoint Formula:(x1+x2)/2,(y1+y2)/2

Answer: (-1,-1)

Part B: We know that the midpoint is (-1,-1). C is (2,7) and D is (x,y)

So redo the midpoint formula with both C and D.

(2+x)/2=-1

2 + x =-2; x=-4

(7+y)/2=-1

7 + y=-2; y=-9

Hope this helps!

Answer 2
Answer:

Formula for the coordinates of the midpoint of the AB sector:

A(x_A,\ y_A);\ B(x_B;\ y_B)\n\nM_(AB)\left((x_A+x_B)/(2);\ (y_A+y_B)/(2)\right)

A(-8,\ 7),\ B(6,\ -9)\n\nM\left((-8+6)/(2);\ (7+(-9))/(2)\right)\to M\left((-2)/(2);\ (-2)/(2)\right)\to M(-1;\ -1)

Answer: The picture 1. M(-1, -1).


C(2,\ 7),\ M(-1,\ -1)\n\n(2+x)/(2)=-1\ ;\ (7+y)/(2)=-1\ \ \ \ |\cdot2\n\n2+x=-2\ ;\ 7+y=-2\n\nx=-4\ ;\ y=-9\n\nD(-4;\ -9)

Answer: The picture 2. D(-4, -9).




Related Questions

A number cube has faces labeled 1 - 6. What is the probability of rolling a 2 on the number cube and landing on a 4 on this spinner?On the spinner there is a 6,2,4,4,4,4 sorry the pic of the spinner won't show I think the answer is 2/3
Wenty-seven minus 3/2 of a number (x) is not more than 36. What is the number?
Which expression represents the product of unknown number and 19?
WILL NAME BRAINLIEST!The probability of drawing two red balls from a jar at random without replacement is 3/10. The probabilty of drawing a red ball first is 9/16. What is the probability of drawing a second Redball, given that the first ball drawn was red?A. 69/80B. 8/15C. 21/80D. 27/160
It took a space shuttle 8 minutes 36 seconds to launch and reach outer space. How many seconds did it take? give u 1009 points later I promise

How many centimeters is 100 meters

Answers

one meter is 100 centimeters. 100 meters is then 100*100, that's 10000, or ten thousand centimeters.
100 M=10000 Cm
This is because 1M=100 CM
Hope this helps!!!!!! :)

A small bar of gold is a rectangular prism that measures 40 mm. by 25 mm. by 2 mm. one cubic mm. of gold weights about 0.0005 ounces. find the volume in cubic mm. and the weight in ounces of this small bar of gold.

Answers

Volume = length times width times height
Volume = 40 mm times 25 mm times 2mm
Volume = 2000 cubic mm (If you want to write it in a different unit, 2 cubic meters)
One cubic mm = 0.0005 ounces
2000 cubic mm = weight of one cubic mm times 2000
2000 cubic mm = 0.0005 times 2000
2000 cubic mm weighs 1 ounce

7 percent as a decimal

Answers

Since 0.7 is 7/10, divide by ten to find 7/100, which is 0.07. Move decimals to the right.

4(2x-3) = use a property to write equivalent expression

Answers

This property is called the distributive property; multiplication can be distributed over addition (subtraction is an addition of a negative number)

and the equivalent expression is this one:

4*2x-4*3

we can simplify this;

8x-12

this expression is equivalent to the one in the question!

Solve the system of equations.
y= 2x
y= x^2 - 15

Answers

Answer:

Since both equations are equal to each other given that they are both equal to y, you can say that . . .

2x = x^2  - 15

x^2 - 2x - 15 = 0

(x-5) (x+3) = 0

Zero Product Property

x = 5 ; x = -3

Solve for y:

y = 2(5) ; y = 2(3)

y = 10 ; y = 6

Please mark for Brainliest!! :D Thanks!!

For more questions or more information, please comment below!

The bull's-eye on a target has a diameter of 3 inches. The whole target has a diameter of 15 inches. What part of the whole target is the bull's-eye? Explain

Answers

Hi Trillstone!

Hoping I'm looking at this correctly, but I'll do my best!

So we have a target with a diameter of 15 in., and a bull's-eye with a diameter of 3 in.  We're basically looking for what 3 in. is to 15 in. in terms of size.  So here we go:

First we're going to need to know the area of a circle, which is: Area = πr².  
We're going to take the area of both the whole target, and then just the bullseye.

Area of Whole Target:  π(15/2)² ⇒ π(7.5)² = 176.71 in³.
Area of Bullseye: π(3/2)² ⇒ π(1.5)² = 7.07 in³.

So far so good? (It's late around here so I'm sorry if I'm missing steps!)

Now from here, all we have to do is divide the area of the bullseye by the area of the target to find our answer.

⇒ 7.07 / 176.71 = .04 

In other terms, the bullseye takes up around 4% of the target.

-Hope this helps and please correct me if this turns out to be incorrect!