What is the name of the shape of the graph of a quadratic function? A. hyperbola B. parabola C. line D. quadratic

Answers

Answer 1
Answer:

we are given

graph of a quadratic function

Quadratic function:

Those function which has degree=2

we can write it as

y=ax^2+bx+c

Since, the degree is 2

so, the shape of the curve will be parabolic

so, option-B.........Answer


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What is the value of z so that -9 and 9 are both solution of x^2+z=103-22 3 22 184

Rewrite the set T by listing its elements. Make sure to use the appropriate set notation. T={[ z| z is an interger and -4≤z<0}

Answers

Based on the given above, the set T is composed of the integers that are between -4 and 0; with -4 being included. Rewriting this set by using the Roster Method gives us an answer of,
                              T = {-4, -3, -2, -1}

Find the degree of the monomial. 6x8y5

Answers

Answer:

13

Step-by-step explanation:

We have been given the monomial 6x^8y^5

Here the variables are x and y.

In order to find the degree this monomial, we add the exponents of the variables x and y.

Exponent of x = 8

Exponent of y = 5

Therefore, the degree of the monomial is

Degree = exponent of x + exponent of y

Degree = 8 + 5

Degree = 13

. 6x⁸y⁵ ← x is a factor 8 times, and y is a factor 5 times, so the degree is 8+5=13 
 13 

How can i solve this
f:d->R
f(x)=x at power2/x-1

Answers

x - 1 is not null => x is not 1 => D = R - {1};

Complete the following question:Order these numbers in ascending order.

-5.97, 600, 205, 456.98, -45.9

Answers

Answer:

-45.9 , -5.97 , 205 , 456.98 , 600

Weather balloons are filled with hydrogen and released at various sites to measure and transmit data such as air pressure and temperature. A weather balloon is filled with hydrogen at the rate of 0.1 ft3/s. Initially, the balloon has 5 ft3 of hydrogen. Find a linear function that models the volume of hydrogen in the balloon after t seconds.

Answers

Answer:

Linear function that models the volume of hydrogen in the balloon after t seconds is V(t) = 5 + 0.1t

Step-by-step explanation:

Initial volume of hydrogen in the balloon = 5 ft³

Rate at which hydrogen is filling in the balloon = 0.1 ft³/s

Volume after 1 second = 5 + 0.1 x 1

Volume after 2 seconds = 5 + 0.1 x 2

Volume after 3 seconds = 5 + 0.1 x 3

Volume after 4 seconds = 5 + 0.1 x 4

Volume after 5 seconds = 5 + 0.1 x 5

Similarly

Volume after t seconds, V(t) = 5 + 0.1 x t = 5 + 0.1t

Linear function that models the volume of hydrogen in the balloon after t seconds is V(t)=5 + 0.1t

Help please?If sin O = -sqrt3 over 2 and n < O < 3 pi over 2, what are the values of cos O and tan O?​

Answers

Answer:

  • cos(θ) = -1/2
  • tan(θ) = √3

Step-by-step explanation:

You know that ...

  • cos(θ)² = 1 - sin(θ)²
  • tan(θ) = sin(θ)/cos(θ)
  • cosine is negative in the third quadrant (where π < θ < 3π/2)

Using what you know about the relationships of these trig functions, you can find ...

  cos(θ)² = 1 - ((-√3)/2)² = 1 - 3/4 = 1/4

  cos(θ) = -1/2 . . . . . negative square root of 1/4

__

  tan(θ) = sin(θ)/cos(θ) = ((-√3)/2)/(-1/2)

  tan(θ) = √3