CHEMISTRY HIGH SCHOOL

How many moles of NaCl are contained in 100.0 mL of a 2.0 M solution?

Answers

Answer 1

Answer:

Answer: -

0.2 moles of NaCl are contained in 100.0 mL of a 2.0 M solution

Explanation: -

Strength of NaCl = 2.0 M

Volume of NaCl solution = 100.0 mL

= $(100)/(1000)$

= 0.1 L

Number of moles of NaCl = volume of NaCl x Strength of NaCl

= 0.1 L x 2.0 M

= 0.2 moles

0.2 moles of NaCl are contained in 100.0 mL of a 2.0 M solution

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What is the symbol for an atom containing 20 protons and 22 neutrons?

Answers

it is an isotope of Calcium, which has the symbol Ca

Answer:

calcium

Explanation:

Which type of radiation is identical in mass and charge to a helium nucleus?a. beta
b. alpha
c. proton
d. positron

Answers

The correct answer is option B. Alpha radiation is identical in mass and charge to a helium nucleus. Alpha particle contains two protons and neutrons. It is the same as giving out a doubly-ionized helium atoms.

What is true about Carbon-14 and Carbon-12?a. The mass of the Carbon-14 sample is less than the Carbon-12 sample, but the reactivity of both samples was the same.
b. The mass of the Carbon-14 sample is greater than the Carbon-12 sample, but the reactivity of both samples was the same .
c. The reactivity of the Carbon-14 sample is less than the Carbon-12 sample, but the mass of both samples was the same.
d. The reactivity of the Carbon-14 sample is greater than the Carbon-12 sample, but the mass of both samples was the same.

Answers

Answer:

Explanation:

Correct: b. The mass of the Carbon-14 sample is greater than the Carbon-12 sample, but the reactivity of both samples was the same .

- C-14 has two additional neutrons, so is heavier than C-12. The chemical properties will be the same, however.

two children are playing tag. Child A who is doing the chasing can run 100m in 24 seconds Child B is running away from child A and can run 64m in 21 seconds. How fast can each child run, and if both of the children do not slow down, will child A be able to catch child B?

Answers

Child A runs at 4.1667 meters per second and child B runs at 3.048 meters per sec. If they do not slow down Child A will be able to catch child B.

What sample is a pure substance?A. a test tube of zinc oxide.b. a container of zinc and oxygen.
c. a flask of pond water.
d. a jar of soil.

Answers

The correct answer is A. A test tube of zinc oxide. Zinc oxide is a compound which is a pure substance composed of two or more elements. They can only be separated or broken down into its individual elements or smaller compounds by chemical means. Therefore, the answer is a test tube of zinc oxide.

The sample that is a pure substance is:A. a test tube of zinc oxide.

What sample is a pure substance?

A pure substance consists of only one type of substance with uniform properties throughout. In this case, a test tube of zinc oxide would be a pure substance. Zinc oxide (ZnO) is a chemical compound made up of zinc (Zn) and oxygen (O) atoms in a fixed ratio. It has a specific chemical formula and a consistent composition, making it a pure substance.

On the other hand:

B. A container of zinc and oxygen would be a mixture since it contains two different substances, zinc and oxygen, in their elemental forms.

C. A flask of pond water is a mixture because it contains a combination of different substances, such as water, dissolved minerals, microorganisms, and organic matter.

D. A jar of soil is also a mixture since it consists of a combination of various components, including minerals, organic matter, water, air, and possibly microorganisms.

Therefore, the correct answer is A. a test tube of zinc oxide, which represents a pure substance.

Learn more about pure substances at:

brainly.com/question/24411600

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How much calcium hypochlorite (65% strength) is needed to make 200 L of 2% hypochlorite solution? (Assume that a 1% solution is equivalent to 10,000 mg/L concentration)

Answers

To solve this we use the equation,

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

65 x V1 = 2 x 200 L

V1 = 6.15 L

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