The point that is not the solution to the system of inequalities is (2, 3), the correct option is A.
A system of Inequality is a set of inequalities in one or more variables.
The inequalities in the graph have a common solution shown by the shaded area.
The points (1,3), (0,3) and (0,4) lie in the shaded region.
Point (2,3) is out of the shaded area.
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For a point to be a solution, it has to be on the green shaded area including the solid red line to the left above the intersection of the lines but not the dashed red line to the right.
(2, 3) is outside the shaded area, so it is not a solution.
(1, 3) is inside the green shaded area, so it is a solution.
(0, 3) is on the red line above the intersection, so it is a solution.
(0, 4) is inside the green shaded area, so it is a solution.
Answer: A. (2, 3)
(3xy) (7xy^2)
= 21(x^2)(y^3) is the simplified expression represents the number of colored tiles
Answer:
2/5
Step-by-step explanation:
Step 1:
2/3 ÷ 5/3 Equation
Step 2:
2/3 × 3/5 Reciprocal
Answer:
2/5 Multiply
Hope This Helps :)
2
sin
x
at the point (π/6,1)
π
6
1
.
The equation of this tangent line can be written in the form y=mx+b
y
m
x
b
where
To find the equation of the tangent line to the curve y=2sinx at the point (π/6,1), we take the derivative to find the slope and then use the point-slope form of the line equation. The result is y = √3x + 1 - √3π/6.
The subject of this question is calculus and focuses specifically on finding the equation of the tangent line to the curve y=2sinx at a given point. To do this, we use the formula y=mx+b.
Firstly, the slope of the tangent line is obtained by taking the derivative of the function at the point of tangency. The derivative of y=2sinx is y'=2cosx. For the given point (π/6,1), the slope (m) would be 2cos(π/6) = √3.
Secondly, we use the point-slope form of the line equation to find b. Inserting the values of the slope (m) and the given point into the equation, we get 1 = √3(π/6) + b. Solving for b gives b = 1 - √3π/6.
Finally, the equation of the tangent line is y = √3x + 1 - √3π/6.
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b.d = f(c) = 100 + c.
c.c = f(d) = 100d.
d.c = f(c) = 100d.
e.d = f(c) = 100 – d
For this case we have the following variables:
d: number of days
c: total number of cars
We know that an amount of 100 cars per day is produced.
Therefore, the equation that models the problem is:
We can write this equation as a function of the number of days.
Therefore, by rewriting the equation we have:
Answer:
An equation that represents the number of cars as a function of the number of days is:
option c