Answer:- A. is not the correct formula.
Explanations:- Charge for Ba is +2 and charge for O is -2, Here the charges are in equal and opposite so their ratio is 1:1 and hence the formula must be BaO and not .
Rest of the formulas are correct as charge for Ca is +2 and charge for N is -3 . On criss cross we get the formula .
Charge for K is +1 and charge for Cl is -1 and so KCl is correct.
Charge for Li is +1 and that for S is -2. On criss cross we get the formula .
Answer:
I don't know
Explanation:
mixture of iron powder and sulphur heated it glows because sulphur and iron are more reactive metals that they shine and sulphur can react with water produce fire it's write
The correct answer fro above statement is:
Some elements in the atmosphere start the body and are consistent when they are dropped. Others are diminishing. Degradation stocks may be more lethal or less virulent than the first chemical. Other chemicals are deposited momentarily in the organs and are discharged shortly after. After a while, most chemicals and degradation stocks are ordered of as body waste, in the stool, urine, sweat and breathed air.
Answer:
false
Explanation:
Answer:
-909.3KJ/mole
Explanation:
The heat of reaction is accessible from the heat of formation of reactants and products using the formula below:
ΔH = Σ ΔHf products - Σ ΔHf reactants
Before we proceed, it is important to know that the enthalpy of formation of element is zero ,be it a single element or a molecule of an element.
From the reaction for the formation of sulphuric acid, we know we need to know the heat of formation of sulphur (vi) oxide and water. The examiner is quite generous and have us for water already.
Now we need to calculate for sulphur (vi) oxide. This is calculated as follows:
We first calculate for sulphur(iv)oxide. This can be obtained from the reaction between sulphur and oxygen. The calculation goes thus:
ΔH = Σ ΔHf products - Σ ΔHf reactants
ΔH = [ 1 mole suphur(iv) oxide × x] - [ (1 mole of elemental sulphur × 0) + (1 mole of elemental oxygen × 0]
We were already told this is equal to -296.8KJ. Hence the heat of formation of sulphur(iv) oxide is -296.8KJ.
We then proceed to the second stage.
Now, here we have 1 mole sulphur (iv) oxide reacting with 0.5 mole oxygen molecule.
We go again :
ΔH = Σ ΔHf products - Σ ΔHf reactants
ΔH = [ 1 mole of sulphur (vi) oxide × y] - [ (1 mole of sulphur (iv) oxide × -296.8) + (0.5 mole of oxygen × 0)].
We already know that the ΔH here equals -98.9KJ.
Hence, -98.9 = y + 296.8
y = -296.8KJ - 98.9KJ = -395.7KJ
We now proceed to the final part of the calculation which ironically comes first in the series of sentences.
Now, we want to calculate the standard heat of formation for sulphuric acid. From the reaction, we can see that one mole of sulphur (vi) oxide, reacted with one mole of water to yield one mole of sulphuric acid.
Mathematically, we go again :
ΔH = Σ ΔHf products - Σ ΔHf reactants
ΔH = [ 1 mole of sulphuric acid × z] - [( 1 mole of sulphur vi oxide × -395.7) + ( 1 mole of water × -285.8)].
Now, we know that the ΔH for this particular reaction is -227.8KJ
We then proceed to to open the bracket.
-227.8 = z - (-395.7 - 285.8)
-227.8 = z - ( -681.5)
-227.8 = z + 681.5
z = -227.8-681.5 = -909.3KJ
Hence, ΔH∘f for sulphuric acid is -909.3KJ/mol
(2) neutron (4) positron
The subatomic particle which will be attracted by a positively charged object is: Choice 3: Electrons.
By law of electricity; like charges repel while unlike charges attract.
In essence, the subatomic particle which will be attracted to a positively charged object is a negatively charged particle.
Since, protons are positively charged, neutrons have no charge, positrons are positively charged but electrons are negatively charged,
The subatomic particle which will be attracted by a positively charged object is; Electron.
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well in this case its percipitation rain hail sleet snow itll set like water after so long it dissolve itll turn into gases
Answer : The structural formula of 2-pentyne is shown below.
Explanation :
Structural formula : In the structural formula, the bonding and type of bonds which holds the atoms in molecule together are shown.
The given name of compound is, 2-pentyne.
A suffix '-yne' present at the end of the name represent the alkyne group.
For the number of carbon atom, we use prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.
In this compound, the parent chain is 5 membered and a triple bond is present at 2nd position of the parent chain.
Thus, the structural formula of 2-pentyne is shown below.