Andrew purchased a car for $19,500 the value of tge car depreciates at a rate of 8.6% each year which equation models the value of andrew car y after x years

Answers

Answer 1

Answer:

If the value depreciates 8.6%, it is 91.4% of what it was the year before. The value can be modeled by-

y = 19,500(0.914)^x

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F(x)=x^3+ax^2+bx+3 where a and b are constants. bx Given that when f (x) is divided by (x+2) the remainder is 7, (a) show that 2a-b=6 Given also that when f (x) is divided by (x-1) the remainder is 4. (b) Find the value of a and the value of b I don't know how solve it :(((((((

Which of the following is the most appropriate unit to describe the rate at which water flows over Niagara Falls? Day per billion gallons, because the independent quantity is volume of water in billion gallons and dependent quantity is time in days

Billion gallons per day, because the independent quantity is volume of water in billion gallons and dependent quantity is time in days

Billion gallons per day, because the independent quantity is time in days and dependent quantity is volume of water in billion gallons

Day per billion gallons, because the independent quantity is time in days and dependent quantity is volume of water in billion gallons

Answers

I'd have to say the second option, "Billion gallons per day, because the independent quantity is volume of water in billion gallons and dependent quantity is time in days"

Answer:

The answer is C, "Billion gallons per day, because the independent quantity is time in days and dependent quantity is volume of water in billion gallons"

Step-by-step explanation:

Pv=kt solve for v
can anyone help

Answers

Hi Walker

pv=kt

Divide both sides by p

pv/p=kt/p

v= kt/p

I hope that's help:0

The expression 1/2 times(4+8) represent the number of hours Mrs nakos work that last week of school.evaluate the expression to find the number of hours she works that week

Answers

The expression $(1)/(2) * (4 + 8)$ represents the number of hours Mrs. Nakos worked during the last week of school. When expression evaluated, it equals 6 hours. So, Mrs. Nakos worked 6 hours that week.

To find the number of hours Mrs. Nakos worked during the last week of school, you can evaluate the expression $(1)/(2) * (4 + 8)$ step by step:

1. Start by evaluating the expression inside the parentheses:

$4 + 8 = 12$

2. Now, you have the expression $$ (1)/(2) * 12 $.$ To calculate this, multiply 12 by
$(1)/(2)$ since dividing by 2 is the same as multiplying by $$ (1)/(2) $:$
$(1)/(2) * 12 = 6$

So, Mrs. Nakos worked 6 hours during the last week of school.

The expression $(1)/(2) * (4 + 8)$ represents the number of hours worked, and when evaluated, it equals 6 hours. Therefore, Mrs. Nakos worked 6 hours that week.

For more such questions on evaluating expressions:

brainly.com/question/28531345

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1\2times(4+8)
4+8=12
12divide2=6
6times7=42

*for 1\2 you can divide by 2 or multiply by .5

1.What is the simplified form of each expression?7x^–8 × 6x^3

a. 42/x^5
b. 1/42x^5
c. 42x^11
d. 13x^–5

(–2x8) · 3y9 · 2x4

a. 3x^12y^9
b. –12x^72y^9
c. –12xy^21
d. –12x^y^9

2. Find the simplified form of the expression. Give your answer in scientific notation.

(8 x 10^7) (7 x 10^4)

a. 1.5 × 10^12
b. 5.6 × 10^12
c. 1.5 x 10^29
d. 5.6 x 10^29

(7 × 10^–4)(9 × 10^–10)

a. 6.3 × 10^–13
b. 63 × 10^–13
c. 6.3 × 10^–15
d. 6.3 × 10^–16

Answers

Answer with explanation:

Ques 1)

We are given a expression as:

$7x^(-8)* 6x^3$

It could also be written as:

$(7* 6)* x^(-8)* x^3\n\n\n=42* x^(-8+3)\n\n\n=42x^(-5)\n\n\n=(42)/(x^5)$

Option: a is the answer.

$(-2x^8)* 3y^9* 2x^4$

which is solved as follows:

$(-2* 3* 2)* x^8* y^9* x^4\n\n\n=-12x^(8+4)* y^9\n\n\n=-12x^(12)y^9$

Ques 2)

The expression is:

$(8* 10^7)(7* 10^4)$

It is solved as:

$=(8* 7)* 10^7* 10^4\n\n\n=56* 10^(7+4)\n\n\n=56* 10^(11)\n\n\n=5.6* 10^(12)$

Option: b is the answer.

$(7* 10^(-4))(9* 10^(-10))$

On simplifying:

$=7* 9* 10^(-4)* 10^(-10)\n\n\n=63* 10^(-4-10)\n\n\n=63* 10^(-14)\n\n\n=6.3* 10^(-14+1)\n\n\n=6.3* 10^(-13)$

Option: a is the answer.

What is the equation of a line that goes through the point (4, 2) and is parallel to the line given by the equation y = 2x + 6?y = 4x - 6
y = -2x + 6
y = 2x - 6
y = -2x - 6

Answers

y=2x-6

Parallel lines have equal gradients

Hello,
Answer C

y-2=2(x-4)
==>y=2x-6

The length and width of a rectangle have a sum of 90. What dimensions give the maximum area?

Answers

$w-width\nl-length\n\n2w+2l=90\n2l=90-2w\ \ \ \ /:2\nl=45-w\n\nA=wl\to A=w(45-w)=45w-w^2$

$Area\ of\ a\ rectangle\ is\ a\ square\ function.\nThe\ maximum\ area\ is\ equal\ to\ the\ y-coordinate\ of\ vertex\nand\$

2( l + w) = 90, where l, w are dimensions of the rectangle => l + w = 45;
The maximum area is obtain when l = w;
Then l = w = 45/2 = 22.5

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