Let
A (0,-2) B (1,-3) C (2,-4) D ( 3,-5) E (4,-6)
using a graph tool
see the attached figure N 1
case a) exponential
see the attached figure N 2
case b) quadratic
see the attached figure N 3
case c) linear
see the attached figure N 4
case d) linear
see the attached figure N 5
therefore
the answer is
the case c) linear
Answer:
Which function best models the data in the graph?
C. Y=10.2x
What is the shape of the following cross section????
The shape of the triangle is the cross-section part of the given figure. Thus, option A is correct.
The cross-section part of the given figure could be the shape fro the inscribed figure.
Here we can see that the three-dimensional figure inscribed in the square is a cone.
The right circular cone is the cone in which the line joining peak of the cone to the center of the base of the circle is perpendicular to the surface of its base.
But for the plane of the square, the triangle is the cross-section part of the given figure.
Learn more about shape here;
#SPJ2
Answer:
Triangle
Step-by-step explanation:
Look at the shape of the red part
what is the expression??
B. y = 12.75x
C. y = 12.75 + x
D. y = 12.75/x
The correct option is B. y=12.75x
cuz, y = total earnings
and x = hours worked
so total earnings(y) should be equal to the amount of money paid for an hour(12.75) * number of hours worked
What is the length of a straight line between the school and the fire station? Round to the nearest tenth.
Part B
The hospital is 3.1 miles west of the fire station. What is the length of a straight line between the school and the hospital? Round to the nearest tenth.
Answer:
a. The length of a straight line between the school and the fire station is 4.6 miles
b. The length of a straight line between the school and the hospital is 2.1 miles
Step-by-step explanation:
See attachment
Given.
Distance between the school and the town hall = 4.3 miles directly east
Distance between the fire station and the town hall = 1.7 miles directly north.
The length of a straight line between the school and the fire station is calculated by solving the length of hypotenuse of the right angled triangle (see attachment A)
Using Pythagoras theorem;
x² = 1.7² + 4.3²
x² = 2.89 + 18.49
x² = 21.38 --- Take square roots
x = 4.6 miles
The length of a straight line between the school and the fire station is 4.6 miles
b.
The length of a straight line between the school and the hospital is calculated by solving the length of hypotenuse of the right angled triangle (see attachment B)
Using Pythagoras theorem;
x² = 1.7² + 1.2²
x² = 2.89 + 1.44
x² = 4.33 --- Take square roots
x = 2.1 miles
The length of a straight line between the school and the hospital is 2.1 miles