The solution set of axequalsb is the set of all vectors of the form wequalspplusbold v subscript h, where bold v subscript h is any solution of the equation axequals0.

Answers

Answer 1

Answer: Answer : Incorrect

Explanation : In the given solution set of Ax = b;
is set of all vectors to form w= p + $V_(h)$
here $V_(h)$ is is any solution of the equation Ax = 0;

this stands to be incorrect, as the correct would only exists when some vector p is found to be like this Ap=b

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After doing multiple titrations, your NaOH solution is determined to have a mean concentration value of 0.100 M. Given you are to assume your unknown acid is 75.0% KHP, how many grams of your unknown will you need to use 15.00 mL of your 0.100 M standardized NaOH

Answers

Answer: The mass of unknown acid needed is 0.230 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaOH solution = 0.100 M

Volume of solution = 15.00 mL = 0.015 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.100M=\frac{\text{Moles of NaOH}}{0.015L}\n\n\text{Moles of NaOH}=(0.100mol/L* 0.015L)=0.0015mol$

The chemical reaction for the reaction of KHP and NaOH follows

$KHC_8H_4O_4(aq.)+NaOH\rightarrow KNaC_8H_4O_4(aq.)+H_2O(l)$

By Stoichiometry of the reaction:

1 mole of NaOH reacts with 1 mole of KHP.

So, 0.0015 moles of NaOH will react with = $(1)/(1)* 0.0015=0.0015mol$ of KHP

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of KHP = 0.0015 moles

Molar mass of KHP = 204.22 g/mol

Putting values in above equation, we get:

$0.0015mol=\frac{\text{Mass of KHP}}{204.22g/mol}\n\n\text{Mass of KHP}=(0.0015mol* 204.22g/mol)=0.306g$

We are given:

Mass of unknown acid = 75 % of Mass of KHP

So, mass of unknown acid = $(75)/(100)* 0.306=0.230g$

Hence, the mass of unknown acid needed is 0.230 grams

Determine the gram formula mass of the product

Answers

For the whole set of problems, always remember the Avogadro’s number is 6.023*10^23 units per mole of a substance. Units could be atoms, molecules or formula units.

The first question asks for the number of molecules of NaNO3. The molar mass of NaNO3 is 85 grams per mole. So,

150g NaNO3(1mole NaNO3/85 grams NaNO3)(6.023*10^23 molecules/1mole NaNO3)=1.063*10^24 molecules of NaNO3

5.7*10^46 molecules of NaNO3(1mole NaNO3/6.023*10^23 molecules)(85 grams NaNO3/1mole NaNO3) = 8.044*10^24 grams NaNO3

For the molar mass of water, we have 18.02grams per mole.

301 moles H2O(18.02 grams H2O/1 mole H2O) = 5424.02 grams H2O

For the molar mass of sulfuric acid, we have 98.08 grams per mole.

25g H2SO4(I mole H2SO4/98.08g H2SO4) = 0.2549 mole H2SO4

For the molar mass of Ca(OH)2, we have 74.1 grams per mole.

252gCa(OH)2(1mol/74.1g)(6.023*10^23/1mol) = 2.048*10^24 molecules of Ca(OH)2

For the molar mass of calcium, we have 40 grams of Ca per mole.

6.7*10^35 atoms Ca(1 mole Ca/6.023*10^23 atoms)(40g Ca/1mol Ca) = 4.45*10^13 grams Ca

A student makes a ball-and-stick model of a propane molecule, as shown below. The black balls represent carbon atoms, and the white balls represent hydrogen atoms.

Answers

Answer:

Explanation:

No sure I tried

Final answer:

A propane molecule's structure can be understood through the ball-and-stick model where carbon and hydrogen atoms play distinct roles leading to different alkyl groups.

Explanation:

The ball-and-stick model of a propane molecule is built using black spheres to indicate carbon atoms and white spheres for hydrogen atoms. In propane, each of the six equivalent white spheres (hydrogen atoms) are bonded to a black sphere (carbon atom) connected to one other black sphere (carbon atom). The remaining two hydrogen atoms are of a different type as they are bonded to a carbon atom (black sphere) that is bonded to two other carbon atoms. They are represented as purple spheres in this explanation. Adjacently, in 2-methylpropane, we find nine similar hydrogen atoms, but notably, one that differs - represented as a green sphere which is bonded to a carbon atom connected to three other carbon atoms. This unique arrangement allows for the formation of different alkyl groups when certain hydrogen atoms are removed.

Learn more about Propane Structure here:

brainly.com/question/11219225

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A 10.35g piece of copper metal was heated to 85.5 degrees C and then placed into 23.6g of water. the initial temperate of the water was 18.3 degrees C. what was the final temperature?

Answers

Answer:

$T_F=20.91^(\circ)C$

Explanation:

For this problem we have to start with the heat equation:

$Q=mCp$ ΔT

In which the delta symbol is:

ΔT= $T_f_i_n_a_l-T_i_n_i_t_i_a_l$

All the heat from copper would be transfer into the water, so:

$Q_m_e_t_a_l=-~Q_w_a_t_e_r$

Now, we can identify the variables:

$m~_C_u=10.35~g$

$m~_H_2_O=23.6~g$

$T_i~_C_u=85.5^(\circ)C$

$T_i~H_2O=18.3^(\circ)C$

$Cp~_C_u~=0.385(J)/(g^(\circ)C)$

$Cp~_H_2_O~=4.184(J)/(g^(\circ)C)$

When we put all together in the equation we will have:

$(10.35~g)*(0.385(J)/(g^(\circ)C))*(T_F-85.5^(\circ)C)=-(23.6~g)*(4.184(J)/(g^(\circ)C))*(T_F-18.3^(\circ)C)$

$3.99~T_F-~340=-98.74~T_F+1806.99$

$3.99~T_F+~98.74~T_F=340+1806.99$

$102.72~T_F=2147.68$

$T_F=20.91^(\circ)C$

We know that the heat that escapes the copper metal is equal to the heat that is added to the water bath.

Thus we can use the MC∆T formula to solve for the final temperature
We need to set up the formula for both the change in temperature of the copper as well as the water
thus
Mass(Cu) * Specific Heat capacity(Cu) * (Final temp - initial temp)(Cu) =
Mass(H2O) * Specific Heat of Water(H2O) * (Final - initial temp)(H2O)

Now we can substitute the given info.
specific heat of copper = 0.386 and water is 4.184
10.35g * 0.386 * (x - 85.5) = 23.6g * 4.184 * (x - 18.3)
Now You just need to solve for X. Also remember to take the absolute value of the left side as it will become negative but really the change in heat or ∆H is equal

Which of the following will stay constant, no matter if the substance is in the solid, liquid, or gas state? volume shape temperature mass

Answers

Answer : The correct option is, Mass

Explanation :

As we know that there are 3 states of matter :

Solid state : It is a state in which the particles are closely packed and does not have any space between them. This state have a definite shape and volume.

Liquid state : It is a state in which the particles are present in random and irregular pattern. The particles are closely arranged but they can move from one place to another. This state have a definite volume but does not have a fixed shape.

Gaseous state : It is a state in which the particles are loosely arranged and have a lot of space between them. This state have indefinite volume as well as shape.

If we are taking 100 grams of ice then after melting its mass remains same but its shape, volume and temperature will be changed and after evaporation its mass remains same but its shape, volume and temperature will be changed.

Hence, the mass will stay constant, no matter if the substance is in the solid, liquid, or gas state.

Answer:

The correct answer is mass

Explanation:

Hello!

Let's solve this!

In the solid state, where the molecules occupy a definite place, and remain still, the shape and volume remain constant.

In the liquid state the molecules take the form of the container that contains them. So the shape is not defined but the volume is defined.

In the gaseous state the molecules are disordered, and have neither defined volume nor shape.

In all three states the mass remains constant.

The temperature causes the change of state.

We conclude that the correct answer is mass

What does the name 2–butene tell you about this hydrocarbon's molecular structure?A.There are two carbon atoms and all single carbon bonds.

B. There are two carbon atoms and a double carbon bond.

C. There are three carbon atoms and a double carbon bond that starts on the second carbon atom.

D. There are four carbon atoms and a double carbon bond that starts on the second carbon atom.

Answers

Option D. There are four carbon atoms and a double bond that starts on the second carbon atom.

Methane: one carbon
Ethene: two carbons
Propene: three carbons
Butene: four carbons.
Pentene: five carbons

The suffix - ene is used for double bonds.

The number 2- indicates the place of the carbon on which the double bond is located.

Gradpoint answer: a four-carbon hydrocarbon with a double bond between the second and third carbon atoms

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How many protons and electrons are in an atom of sodium whose atomic number is 11?

Sulfur dioxide is a main component of: photochemical smog, thermal inversion, industrial smog.