A chemist has two acid solutions in stock: one is a 50% solution, and the other is a 80% solution. How much of each solution should be mixed to obtain 100 milliliters of a 68% solution?

Answers

Answer 1

Answer: Easy way, visual

50---68---80%
Difference 18 12
Invert order to give ratio of 50% and 80%
Ratio 12 18 = 2:3

So by simple proportion:
volume of 50% needed = 100*2/(2+3)=40 mL
volume of 80% needed = 100*3/(2+3)=60 mL

Algebra way
Let x=volume of 50% needed.
Then
0.50*x+0.80*(100-x) = 0.68(100)
Expand and solve for x
0.5x+80-0.8x = 68
0.8x-0.5x = 80-68
0.3x = 12
x=12/0.3 = 40 mL (volume of 50%)
100-x=100-40=60 mL (volume of 80%)

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Answers

since cube has all sides equal and therefor al sides equal aera and 6 sides
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divide both sides by 6
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hope this helps

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Answers

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Larry and Willa are each reading the same book. Larry has read 2/3 of the book. Willa said that she has read 4/6 of the book, so she read more. Is Willa correct? Explain.

Answers

Willa isn't correct because 2/3 is the same amount as 4/6. You now this because you multiply 2 to both den and num (bottom +Top of a fraction).

Whats 5+5 o-O SCREEEEEEEE

Answers

Answer:

Step-by-step explanation:

If you have 5 apples and Kaky gives 5 more you will have 10 alltogether.

Hope this helps :-)

Louis wants to place carpet in his rectangular basement. The basement has an area of 864 square feet. The width of the basement is 2/3 it's length. What is the length of Louis's basement?

Answers

A=WxL
864 = 2/3 x L x L
864 = 2/3 L^2
864/2/3 = (2/3 L^2)/2/3
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1296=L^2
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A stone wall is a total of 6 feet high. Only 4 of the wall is above ground what part is underground

Answers

2 is underground

hope this helps

2 is underground.....

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