The length of the shortest side of the triangle is 10cm.
It is given that congruent sides of an isosceles triangle are each 1 unit longer than the length of the shortest side, the perimeter of the triangle is the same as the perimeter of a square whose side length is 2 units shorter than the length of the shortest side of the triangle.
All three corresponding sides are equal and all the three corresponding angles are equal in measure.
Let's have the variable x be the length of the shortest side.
To equate to demonstrate this problem:
Longer sides of the triangle is (1+x)
Perimeter = (x-2)*4
Therefore, the equation is 4(x-2)=(1+x)+(1+x)+x
Simplify:
4x-8=2+3x
4x=10+3x
x=10
So, the length of the shortest side of the triangle is 10cm.
Learn more about congruent triangle here:
#SPJ5
This problem, as written, requires a bit of guessing regarding your intentions. My interpretation is that you want to do this division:
2
----------
1 6/7
If that's correct, here's what to do: rewrite 1 6/7 as 13/7 (an improper fraction).
Then divide:
2
-------- This is equivalent to the multiplication (2/1)(7/13) = 14/13 (answer)
13/7
3, plus, j, k, plus, k, cubed when j=2j=2j, equals, 2 and k=6k=6k, equals, 6
Answer:
231
This is the answer take it or leave it
The answer to this question is 11.