Solution:
Step wise solution
Let r1 be the distance from the Earth to the point where
the gravitational accelerations are the same and let r2 be the distance
from the Moon to that point.
Then, r1+ r2 = r12 = 383,000 km.
Let Re be the radius of earth
and let Rm be the radius of moon
Let, ge be the gravity of earth
and let gm be the gravity of moon
The fact that the gravitational attractions by the Earth and the Moon
at this point are equal leads to the equation
gE(Re/r1)=gM(Rm/r2)
9.8(6380/r1)=1.62(1738/r12-r1)
(here, Re=6380, gE=9.8m/s^2, gM=1.62m/s^2 and r12=383,000 km
9.8*6380/(1.62*1738)=r1/(383000-r1)
therefore,
r1=344,770 km
Hope this answer wil help you
Answer:
Calculate the distance between the center of the earth and the center of the moon at which the gravitational force exerted by the earth on an object is equal in magnitude to the force exerted by the moon on the object
Explanation:
solution steps
Answer:
250 newtons i belive.
Explanation:
Answer:220
Explanation:has more mass
B. One space probe has more air resistance than the other.
C. Only one space probe is exerting a gravitational force on the other.
D. One space probe is closer to Jupiter than the other
Answer:
The correct answer is D
Explanation:
Arrhenius bases release hydronium ions in solution.
Arrhenius bases act as proton and hydroxide acceptors.
Arrhenius bases produce only hydroxide ions in solution
Answer:
the 3rd one
Explanation: