Answer:
The investigator needs to add a negative and a positive control. The positive control can be an auxin previously tested on this plant species, and the negative control should be a NON AUXIN SPRAYED plant, it can be sprayed with disstilled water. It is importan that all these plants are exactly under the same conditions (temperature, light, etc.), but with a distance between them that does not allow crossed contamination.
Explanation:
In this experiment, the investigator should establish a control by growing the same plant species without the auxin under the same conditions. This allows them to compare plant development with and without the growth hormone, verifying its effect.
To set up a proper control for this experiment, the investigator should maintain another set of six potted plant seedlings of the same species but without spraying them with auxin. These plants will then be grown under the same ideal conditions for the same duration. This control group will allow the investigator to compare the growth and development of plants without the hormone against those with the hormone, demonstrating any effects the growth hormone may have had.
Controls in experiments like these are crucial because they assist in determining the specificity of the effects of the variables being tested, in this case, the plant hormones. Without a control group, it would be impossible to definitively assign any observed changes to the application of auxin.
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Answer:
your brain
Explanation:
why this is well because no brain your dead it helps you eat sleep breath and pump your heart no brain no HEART ether but thats me
B. to determine the compatibility of the organs of donor and recipient
C. to determine the compatibility of antibodies of donor and recipient
D. to determine the compatibility of the blood vessels of donor and recipient
the answer is A. to determine the compatibility of the blood types of donor and recipient
B : lungs
C : ureters
b. area of square c2 = area of square a2 + area of square b2 + area of defect1 – area of defect2
c. area of square c2 = area of square a2 + area of square b2 – area of defect1 – area of defect2
d. area of square c2 = area of square a2 + area of square b2 + area of defect1+ area of defect2
e. area of square c2 = area of square a2 - area of square b2 + area of defect1 - area of defect2
Answer: c. area of square c2 = area of square a2 + area of square b2 – area of defect1 – area of defect2
(Option C)
Explanation:
The cosine rule helps to determine the different angles and sides of a triangle. The cosine rule is helpful when you need to find the third side of the triangle when the other two sides of the triangle are given and the angle between them.