What is the initial temperature of a gas if the volume changed from 1.00l to 1.10l and the final temperature was determined to be 255?

Answers

Answer 1
Answer: Answer is 231.8 K

Explanation
We can use Charle's law to solve this problem.

Charle's law says"at a constantpressure, the volume of a fixed amount of gas is directly proportional to itsabsolute temperature".

V α T 

Where V is the volume and T is the temperaturein Kelvin of the gas. We can use this for two situations as,
V
/T = V/T

V₁ = 1.00 L
T
₁ =?
V
₂ = 1.10 L
T
₂ = 255 K (Since the unit of the given temperature is missing in the question, thought that the given temperature is in Kelvin)

By applying theformula,
1.00 L / 
T₁ = 1.10 L / 255 K                  
             
T₁ =(1.00 L / 1.10 L) x 255 K
             
T₁ = 231.8 K

Hence, the initial temperature is 231.8 K.

Assumption : the pressure of the gas is a constant. 




Answer 2
Answer:

Hello!

What is the initial temperature of a gas if the volume changed from 1.00l to 1.10l and the final temperature was determined to be 255 ?

We have the following data:

V1 (initial volume) = 1.00 L

V2 (final volume) = 1.10 L

T1 (initial temperature) = ? (in Kelvin)

T2 (final temperature) = 255 K

According to the Law of Charles and Gay-Lussac in the study of gases, in an isobaric transformation, ie when a mass under pressure maintains its constant pressure, on the other hand, as the volume increases, the temperature increases and, if the volume decreases, the temperature decreases (directly proportional to temperature and volume) . We apply the data to the formula of isobaric transformation (Charles and Gay-Lussac), we will see:

(V_1)/(T_1) = (V_2)/(T_2)

(1.00)/(T_1) = (1.10)/(255)

multiply the means by the extremes

1.10*T_1 = 1.00*255

1.10\:T_1 = 255

T_1 = (255)/(1.10)

\boxed{\boxed{T_1 \approx 231.8\:K}}\:\:\:\:\:\:\bf\red{\checkmark}

Answer:

The initial temperature is approximately 231.8 Kelvin

________________________

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Write a balanced nuclear equation for the following: The nuclide uranium-238 undergoes alpha emission.

Answers

Answer:

²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He + Energy

Explanation:

Hello,

When uranium undergoes an alpha decay, it's atomic number is reduced by 2 while it atomic mass is reduced by 4 similar to the elements helium (He) and sometimes alpha decay is represented by a helium atom.

Equation of decay

²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He + Energy

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PLEASE HELP ASAP!!1. what is the pOH of a solution if the pH is 2.23?

A. pOH=13
B. pOH=11.77
C. pOH=8.52
D. pOH=10.52

2. what is the pOH of a solution if the pH is 2.23

A. pOH=1
B. pOH=12
C. pOH=8
D. pOH=9

3. Given a solution of perchloric acid has a concentration of .023M, what is the pH and pOH

A. pH=2.3 and pOH=11.97
B. pH=1.64 and pOH= 12.36
C. pH=4.5 and pOH=9.95

Answers

1) POH=14-2.23=11.77
2)B
3)HClO4=H+ +clo4—
C(H+)=0.023 M
pH=-log[H+]=1.63
POH=14-1.63=12.37

Final answer:

The pH and pOH for a solution are related through the equation pH + pOH = 14. The pOH for solutions with a pH of 2.23 is 11.77, and in a solution of perchloric acid with a concentration of .023M, the pH is 1.64 and pOH is 12.36.

Explanation:

The concept of pOH and pH are related through the equation pH + pOH = 14 at 25 °C. If you have the value of one, you can easily find the other. For your first two questions, the pH of solution is given as 2.23. Therefore, the pOH would be 14 - 2.23 = 11.77. Your answer to both questions 1 and 2 is B. pOH=11.77.

For question 3, the perchloric acid has a concentration of .023M. To find the pH, we calculate -log[H3O+], which gives about 1.64. Therefore, the pOH would be 14 - 1.64 = 12.36. Your answer to question 3 is B. pH=1.64 and pOH=12.36.

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Carbon dioxide and an unknown gas start to effuse from a container and the carbon dioxide takes 4.69 times as long to escape as the unknown gas. What is the identity of the unknown gas?

Answers

Answer: the gas is lighter than CO2 and it is hydrogen

Explanation:Please see attachment for explanation

What is an extensive property? *A property that changes if temperature changes
A property that will NOT change if temperature changes
A property that changes if the amount of substance changes
A property that does NOT change if the amount of substance changes
Help :( pls

Answers

Answer:

A property that changes if the amount of substance changes

Explanation:

An extensive property is a property that depends on the amount of matter in a sample.

Final answer:

An extensive property changes if the amount of substance changes. For instance, mass and volume are extensive properties as they would vary depending on the amount of substance.

Explanation:

An extensive property is a property that changes if the amount of substance changes. For example, mass and volume are extensive properties. If you have two separate samples of a substance, each with a different amount, their mass and volume would be different. On the other hand, the melting point or boiling point of the substance, which are examples of intensive properties, would not change regardless of the amount of substance.

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The vapor pressure of carbon disulfide is 355.6 torr at 25°C. What is the vapor pressure of a solution prepared by dissolving 10.60 g naphthalene (C10H8, Molar Mass = 128.2 g/mol) in 155 mL CS2 liquid (Molar Mass = 76.14 g/mol, density = 1.261 g/mL)? Assume the solution obeys Raoult's law, and treat naphthalene as a nonvolatile solute.

Answers

The vapor pressure of the solution would be as follows:

344.5764 torr

Given that,

Vapor pressure of Carbon Disulfide = 355.6 torr

volume = 155mL ;

density = 1.261 g/mL

Naphthalene's mass = 10.60 g

Naphthalene's molar mass= 128.2g/mol

Now,

We know that

Number of moles= mass/molar mass

Mass= density × volume

Number of moles =(density × volume) / molar mass

So,

Number of moles of Carbon Disulfide = (1.261 × 155) / 76.14

= (195.455 / 76.14)

= 2.567 moles of Carbon Disulfide

Number of moles of Naphthalene:

Number of moles= 10.60 / 128.2

= 0.083

Now,

Total number of moles :

2.567 + 0.083

= 2.65 moles

Mole fraction of each compound in solution :

Carbon Disulfide:

2.567 / 2.65

= 0.969

Naphthalene

0.083 / 2.65

= 0.031

According to Raoult's:

Psolution = Xsolvent × Posolvent

Carbon Sulfide = Solvent

Xsolvent =Mole fraction of solvent

Posolvent =Vapour  pressure of the pure solvent

Psolution= 0.969 × 355.6 torr

= 344.5764 torr

Thus, "344.5764 torr" is the correct answer.

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Answer:

344.5764 torr

Explanation:

Molar mass of naphthalene = 128.2g/mol

Mass of naphthalene = 10.60 g

Carbon disulfide:

Molar mass= 76.14g/mol ;

volume = 155mL ;

density = 1.261 g/mL

Vapour pressure = 355.6 torr

Number of moles = mass / molar mass

CS2:

Mass = density × volume

Number of moles = (density × volume) / molar mass

Number of moles = (1.261 * 155) / 76.14 = (195.455 / 76.14) = 2.567 moles of CS2

Number of moles of C8H10:

Number of moles = 10.60 / 128.2 = 0.083 C8H10

Total number of moles :

2.567 + 0.083 = 2.65 moles

Mole fraction of each compound in solution :

CS2 :

2.567 / 2.65 = 0.969

C8H10:

0.083 / 2.65 = 0.031

According to Raoult's:

Psolution = Xsolvent × Posolvent

CS2 = solvent

Xsolvent = Mole fraction of solvent

Posolvent = Vapour pressure of pure solvent

Psolution = 0.969 × 355.6 torr = 344.5764 torr

If the partial pressure of N2 in a scuba divers blood at the surface is 0.79 atm, what will the pressure be if he/she descends to a depth of 30 meters (4 atm) and stays there long enough to reach equilibrium (b)

Answers

Answer:

If the partial pressure of N2 in a scuba divers blood at the surface is 0.79 atm, what will the pressure be if he/she descends to a depth of 30 meters (4 atm) and stays there long enough to reach equilibrium (b)

Explanation:

for every 3m that the internal pressure is lowered, it increases in an atmosphere approximately, so when the blood pressure of nitrogen decreases 30m, it will increase by approximately 10 atm, being enough there for the body to enter into equilibrium