The rate of change of y is proportional to y. when x=0, y=4 and when x=3, y=10 then the value of y is 12 when x =6.
The two points from the given information are (0, 4) and (3, 10).
Let us find the
=6/3
=2
Now let us find the y intercept to write the equation in slope intercept form.
Consider the point (0, 4) to find y intercept.
Plug in the point values in slope intercept form:
4=2(0)+b
Solve for b:
b=4
The equation in slope intercept form is y=2x+4.
Now let us find the value of y when x=6.
Plug in x as 6 in the equation y=2x+4.
y=2(6)+4
y=12+4
y=16
Hence, the value of y is 16 when x is 6.
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We know x+y=0; so, if x=6 y= -6
Answer:
0.44444444444
Step-by-step explanation:
whats the value of c?
Simplify both sides of the equation
11c+7c -13c = 115
Simplify
5c= 115
Divide both sides by 5
5c/5 = 115/5
c = 23
I hope that's help !
Answer:
$17.82
Step-by-step explanation:
Answer: $232.48
Step-by-step explanation: an equation you could use would be:
125.25+(28.35+78.88)
Add parentheses: 28.35+78.88= 107.23
Add the rest: 125.25+107.23= 232.48
Answer: 216
Step-by-step explanation:
The formula to find the sample size , if prior population proportion is known :-
Given : The prior proportion of defective parts : p= 0.10
Significance level :
Critical value :
Margin of error :
Now, the required sample size will be :-
Hence, the minimum required sample size = 216
To achieve a margin of error of .04 or less with a 95% confidence level when the defect rate is 10%, at least 217 samples need to be taken.
The question pertains to the field of statistics, specifically sample sizes and margin of error. In order to estimate the minimum sample size needed to achieve a desired margin of error of .04 or less, we can use the formula for sample size in proportions: n = (Z^2*p*(1-p))/E^2.
In this formula:
Substitute the values into the formula: n = (1.96^2*0.1*0.9)/(0.04^2), yielding n=216.09.
Since we can't have a fraction of a sample, we round up to get n = 217. Therefore, we need a sample size of 217 to reach a margin of error of .04 or less with a 95% confidence level.
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