MATHEMATICS HIGH SCHOOL

Compare the numbers √11 and 3.7. Use the symbols <,>,or=.

Answers

Answer 1

Answer:

Answer: Hi! here we want to compare the numbers $√(11)$ and $3.7$

and we need to use <,> or =

So the first thing i would look is the square root.

we know that $3^(2) = 9, 4^(2) = 16$

so 3< $√(11)$ <4

now we can see $3.7^(2) = (3 + 0.7)*(3 + 0.7) = (3*3 + 2*0.7*3 + 0.7*0.7) =(9 + 6*0.7 + 0.7*0.7)$

is easy to see that $0.7*6 \geq 0.5*6=3$

then $3.7^(2) = (9 + 0.7*6 + 0.7*0.7) > (9 + 3 + 0.7*0.7) > 9 +3 = 12$

so 3.7^2 > 12, and 12>11

then: $3.7 > √(11)$

You also can use a calculator, but i think this is not the idea of the problem.

Answer 2

Answer: ....................................................

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What is the value of 1 tens and 16 ones

Answers

1 x 10 = 10
16 x 1 = 16
10 + 16 =
26

You have 1 ten (10)
You have 16 ones (10+6)
10+10+6= 26

Find the first five terms of the sequence defined by each of these recurrencerelations and initial conditions.
a) an = 6an-1, a0 = 2
b) an = −2an-1, a0 = −1
c) an = an-1 – an-2, a0 = 2, a1 = −1

Answers

a) The first five terms of the sequence are 2, 12, 72, 432, 2592.
b) The first five terms of the sequence are -1, 2, -4, 8, -16.

c) The first five terms of the sequence are 2, -1, -3, -2, 1.

To find the first five terms of the sequence defined by each of these recurrence relations and initial conditions, we will use the given recurrence relation and initial conditions to find the next terms in the sequence.

a) an = 6an-1, a0 = 2

The first term is given as a0 = 2. We will use the recurrence relation to find the next terms.
a1 = 6a0 = 6(2) = 12
a2 = 6a1 = 6(12) = 72
a3 = 6a2 = 6(72) = 432
a4 = 6a3 = 6(432) = 2592

So, the first five terms of the sequence are 2, 12, 72, 432, 2592.

b) an = −2an-1, a0 = −1

The first term is given as a0 = -1. We will use the recurrence relation to find the next terms.
a1 = -2a0 = -2(-1) = 2
a2 = -2a1 = -2(2) = -4
a3 = -2a2 = -2(-4) = 8
a4 = -2a3 = -2(8) = -16

So, the first five terms of the sequence are -1, 2, -4, 8, -16.

c) an = an-1 – an-2, a0 = 2, a1 = −1

The first two terms are given as a0 = 2 and a1 = -1. We will use the recurrence relation to find the next terms.
a2 = a1 - a0 = -1 - 2 = -3
a3 = a2 - a1 = -3 - (-1) = -2
a4 = a3 - a2 = -2 - (-3) = 1

So, the first five terms of the sequence are 2, -1, -3, -2, 1.

Learn more about Recurrence

brainly.com/question/16931362

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9. What is the least common denominator of 3/4, 4/5, 2/3?

A. 20B. 15C. 60D. 12

Answers

When finding the least common denominator you look at the denominator of the fraction which is the number below the line.

To find the least common denominator in this question you would find the common multiple of 4,5,and 3

Which ever common multiple shows up first is your answer

Multiples of 4,5, and 3 :

4 8 12 16 20 24 28 32 36 40 44 48 52 56 60

5 10 15 20 25 30 35 40 45 50 55 60 65

3 6 9 12 15 18 21 24 27 30 33 36 39 42 45 48 51 54 57 60

The answer to this problem would be 60

Rewrite using a negative exponent.

5/x^2

Answers

13.591409x3 i believe hope it heloped

ActivityThe equation y = x + 1 represents plane A and y = -x + 21 represents plane B, where x is the time in minutes and y is the fuel in tons.

Part A
Go to your math tools and open the Graph tool to graph the two sets of equations. To see where the two lines intersect, change the scale so that the x-axis goes from 0 to 30 and the y-axis goes from 0 to 12. Paste a screenshot of the resulting graph in the answer space.

Part B
At which point do the lines intersect?

Part C
Do the coordinates of the point of intersection satisfy both equations simultaneously?

Answers

Answer:

Part-A: refer to the attachment

Part-B: (10,11)

Part-C: yes

step-by-step explanation:

Part-A:

refer to the attachment

(I used a online graphing calculator to graph the equations which made the work easy)

Part-B:

When two lines share exactly one common point, they are called the intersecting lines and thepointis called thepointof interception

Looking at the graph,we can understand that the two lines share a common point at (10,11),

hence,

The lines intercept at the point (10,11)

PartC:

well, to find the answer of this part, we can consider doing equality check by substituting the value of the point we got.

The point (10,11) means that the left and right hand side of both of the equations i.e $\text{y=x+1 and y=-x+21}$ are equal when x and y equal to 10 and 11 respectively.