When the equation is correctly balanced , the coefficient of O₂ = 3.
The amounts of reactants and products required to satisfy the Law of Conservation of Mass are given in a balanced chemical equation.
This indicates that on the reactant side of the equation, there are the same number atom as there are on the product side of the equation.
In the question the given equation is
C₂H₄+O₂→CO₂+H₂O
When the equation is correctly balanced using smallest whole numbers
C₂H₄+3O₂→2CO₂+2H₂O
To determine if the equation is balanced or not , if we will check the reactant molecules with the product molecules.
C = 2 in reactant and product
O=6 in reactant and product
H=4 in reactant and product
So the equation is balanced
and so the coefficient of O₂ = 3
To know more about the balancing of Equation
#SPJ2
b. hydrogen ion acceptor.
c. electron-pair donor.
d. electron-pair acceptor.
Simplify
6carbon
8Hydrogen
7Oxygen
(2) 35.0% (4) 60.0%
Answer:
The correct option is (2) 35.0%
Explanation:
If we want to calculate the percent composition by mass of nitrogen in NH4NO3 we first need to calculate the mass of nitrogen in one mole of NH4NO3.
Because of the molecular form of NH4NO3 (it has 2 ''N'') we know that one mole of NH4NO3 contains 2 moles of N.
The molar mass of N (nitrogen) is
This means that 1 mole of N contains 14.0067 grams of N.
Because we have 2 moles of N ⇒
We know that in 1 mole of NH4NO3 we have 2 moles of N(28.0134 g of N).
To calculate the percent composition by mass of nitrogen we need to divide the mass of nitrogen in one mole of NH4NO3 by the mass of one mole of NH4NO3 and then multiply it by 100.
We know that in 1 mole of NH4NO3 there are 80.0 g of NH4NO3 (Because of the molar mass data) ⇒
% ≅ 35.0%
We find that the percent composition by mass of nitrogen in NH4NO3 is 35.0%
We conclude that the correct option is (2) 35.0%