MATHEMATICS MIDDLE SCHOOL

Help me out !!!!! Please
Help me out !!!!! Please - 1

Answers

Answer 1
Answer: 4x-t-4 is the final answer.

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Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function Y=2x^2+12x+13
axis of symmetry:
vertex:

Answers

Answer:

Axis of symmetry: –3

Vertex: (–3, –5)

Step-by-step explanation:

For a quadratic function in standard form, the axis of symmetry is a vertical line x=-(b)/(2a). Therefore:

x=-(b)/(2a)=-(12)/(2(2))=-(12)/(4)=-3

For the vertex, –3 is the x-coordinate and we solve for y to find the y-coordinate:

y = 2x² + 12x + 13

y = 2(–3)² + 12(–3) + 13

y = 2(9) + 12(–3) + 13

y = 18 – 36 + 13

y = –5

Therefore, the vertex is (–3, –5).

A class' average on a test was 78. The students in the class scored within 22 of the class average. Which absolute value inequality could be used to find all possible student scores?a.
|−78| ≤ 22


b.
|−22| ≥ 78


c.
|−78| ≥ 22


d.
|−22| ≤ 78

Answers

You can di letter c to find the students absolute value
Option D is the correct answer: I-22I < 78

How to do this table?

Answers

Given:
52 weeks in 1 year.

f(n) = 52n

Hanna's age in year:                      Hanna's age in weeks
1                            f(1) = 52(1)                    52
2                            f(2) = 52(2)                  104                   
3                            f(3) = 52(3)                  156
4                            f(4) = 52(4)                  208
5                            f(5) = 52(5)                  260

11                          f(11) = 52(11)               572

Mumbi is approximately 845 kilometers away from Bangalore, and Mumbai is approximately 1160 km away from Delhi. The distances, measured in centimeters between cities on Allyson’s map are proportional to the real distances.Which of the following could be the the distances on Allyson’s map?

Choose 3 answers

Bangalore to Mumbai: 116.5 cm
Mumbai to Delhi: 174 cm

Bangalore to Mumbai: 42.25
Mumbai to Delhi: 58 cm

Bangalore to Mumbai: 23.4 cm
Mumbai to Delhi: 29 cm

Bangalore to Mumbai: 16.9 cm
Mumbai to Delhi: 23.2 cm

Bangalore to Mumbai: 25.35 cm
Mumbai to Delhi: 34.8cm

Answers

Mumbi is approximately 845 kilometers away from Bangalore, and Mumbai is approximately 1160 km away from Delhi, then the ratio between these distances is

(845)/(1160)=(169)/(232).

A. Bangalore to Mumbai: 116.5 cm;

Mumbai to Delhi: 174 cm

The ratio:

(116.5)/(174)=(233)/(348)\neq (169)/(232)

This option is false.

B. Bangalore to Mumbai: 42.25

Mumbai to Delhi: 58 cm

The ratio is

(42.25)/(58)=(845)/(1160)=(169)/(232)

This option is true.

C. Bangalore to Mumbai: 23.4 cm

Mumbai to Delhi: 29 cm

The ratio is

(23.4)/(29)=(117)/(145)\neq (169)/(232)

This option is false.

D. Bangalore to Mumbai: 16.9 cm

Mumbai to Delhi: 23.2 cm

The ratio is

(16.9)/(23.2)=(169)/(232)

This option is true.

E. Bangalore to Mumbai: 25.35 cm

Mumbai to Delhi: 34.8cm

The ratio is

(25.35)/(34.8)=(507)/(696)=(169)/(232)

This option is true.

Answer: correct options are B, D and E

Answer:

Step-by-step explanation:

Mumbi is approximately 845 kilometers away from Bangalore, and Mumbai is approximately 1160 km away from Delhi, then the ratio between these distances is

A. Bangalore to Mumbai: 116.5 cm;

Mumbai to Delhi: 174 cm

The ratio:

This option is false.

B. Bangalore to Mumbai: 42.25

Mumbai to Delhi: 58 cm

The ratio is

This option is true.

C. Bangalore to Mumbai: 23.4 cm

Mumbai to Delhi: 29 cm

The ratio is

This option is false.

D. Bangalore to Mumbai: 16.9 cm

Mumbai to Delhi: 23.2 cm

The ratio is

This option is true.

E. Bangalore to Mumbai: 25.35 cm

Mumbai to Delhi: 34.8cm

The ratio is

This option is true.

Answer: correct options are B, D and E

Joe found the area of a triangle by writing A=1/2(11 in.)(4 in.), while Kaitlin found the area by writing A=1/2(3 in.)(4 in.) + 1/2( 8 in.)(4 in.). explain how each student approached the problem.

Answers

ok so remember distributive property
a(b+c)=ab+ac so

1/2(11)(4)=1/2(3)4+1/2(8)(4)
aka

(1/2*4)(11)=(1/2*4)(3+8)(1/2*4)(3)+(1/2*4)(8)
the 1/2*4 bit was the 'a' and the 3 was b and 8 was c

A cone and cylinder have the same height and the same base radius. If the volume of the cylinder is 81 cm^3 what is the volume of the cone in cm^3?A) 9
B) 27
C) 78
D)243

Answers

Answer:

The volume of the cone is 27cm^3

Step-by-step explanation:

We know that formulas

Volume of cylinder is

V_1=\pi r^2 h

Volume of cone is

V_2=(1)/(3)\pi r^2 h

we are given

A cone and cylinder have the same height and the same base radius

So, both will have same radius and height

now, we can find ratios

(V_2)/(V_1)=((1)/(3)\pi r^2h )/(\pi r^2h)

now, we can simplify it

(V_2)/(V_1)=(1)/(3)

we are given

the volume of the cylinder is 81 cm^3

so, V_1=81

now, we can plug it and solve for V2

(V_2)/(81)=(1)/(3)

81* (V_2)/(81)=81*(1)/(3)

V_2=27

So, the volume of the cone is 27cm^3
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