This is hard can I get help

Answers

Answer 1

Answer: Same as the last one you asked.

AB + BC = AC. Just think of it like Part + Part = Whole Thing

(2x + 6) + (6x + 5) = 51

Combine like terms:
8x + 11 = 51

Subtract 11 from both sides to get the variable and its coefficient on its own:
8x = 51 - 11
8x = 40

Divide both sides by 8 to isolate the variable:
x = 5

It's asking for us to find BC so now we plug in x = 5 to the equation it gave for BC.

6x + 5
6(5) + 5
30 + 5
35

BC is 35 units long.

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How do i solve this equation:

slope= 4, (-3,3)

Answers

$slope= 4, \ \ (-3,3) \n \n To \ find \ our \ equation \ we \ will \ use \ the \ formula: \n \n y - y _(1) = m(x - x _(1))\n \nwherem \ is \ the \ slope \ and \ (x _(1), y _(1)) \ is \ the \ point \n \nm=4, \ \ x_(1)= -3 , \ \ y_(1) = 3 \n \n y - 3 = 4(x - (-3))$

$y -3= 4(x +3) \n \n y-3 =4x+12\n\ny=4x+12+3\n \n y =4x+15$

$y=mx+b\ \ \ and\ \ \ m-slope\n\n slope= 4\ \ \ \Rightarrow\ \ \ y=4x+b\n\n point:\ (-3,3)\ \ \ \Rightarrow\ \ \ 3=4\cdot(-3)+b\ \ \ \ \Rightarrow\ \ \ b=3+12=15\n\nAns.\ y=4x+15$

What is the equation of a parabola whose vertex is at the origin and whose directrix is y = 3?

Answers

The equation of a parabola whose vertex is at the origin and whose directrix is y = 3 will be y = 12x².

What is the parabola?

It's the locus of a moving point that keeps the same distance between a stationary point and a specified line. The focus is a non-movable point, while the directrix is a non-movable line.

Let the point (h, k) is the vertex of the parabola and a is the focus.

Then the equation of the parabola will be given as,

y = 4a(x - h)² + k

The vertex of the parabola is at the origin, then the equation of the parabola will be

y = 4a(x - 0)² + 0

y = 4ax²

We know that the distance between the directrix - graph and focus graph is the same.

Then the value of focus will be 3.

Then the equation of the parabola will be

y = 4 × 3 × x²

y = 12x²

The equation of a parabola whose vertex is at the origin and whose directrix is y = 3 will be y = 12x².

More about the parabola link is given below.

brainly.com/question/8495504

#SPJ5

Y^2=4*3*X=12X Hope this helps!

Which of the following is always true?1. All trapezoids are similar.
II. All parallelograms are similar.
III. All kites are similar.
IV. All regular quadrilaterals are similar.
O l only
IV only
k
I and III only
O II and IV only
Please help quick

Answers

Answer:

Step-by-step explanation:

A trapezoid has one pair of parallel sides and a parallelogram has two pairs of parallel sides. So a parallelogram is also a trapezoid. A trapezoid is a quadrilateral with one pair of opposite sides parallel. It can have right angles (a right trapezoid), and it can have congruent sides (isosceles), but those are not required. In any isosceles trapezoid, two opposite sides (the bases) are parallel, and the two other sides (the legs) are of equal length (properties shared with the parallelogram). The diagonals are also of equal length.

A parallelogram has adjacent sides with the lengths of and . Find a pair of possible adjacent side lengths for a similar parallelogram. Explanation: Since the two parallelogram are similar, each of the corresponding sides must have the same ratio.

Not only are the corresponding angles the same size in similar polygons, but also the sides are proportional.

The equation of line k is y=-1/5x -1/8. What is the equation of the line that is perpendicular to line k and passes through (0,0)?

Answers

y=-1/5 x-1/8
Gradient, m= -1/5
A line perpendicular will be;
m=15
y=mx+c
Replacing for x and y;
0=5(0)+c
c=0
y=5x

Among the 10 most popular sports, men include competition-type sports - pool and billiards, basketball, and softball - whereas women include aerobics, running, hiking, and calisthenics. However, the top recreational activity for men was still the relaxing sport of fishing, with 41% of those surveyed indicating that they had fished during the year. Suppose 180 randomly selected men are asked whether they had fished in the past year. Suppose 180 randomly selected men are asked whether they has fished in the past year.a. What is the probability that fewer than 50 had fished?
b. What is the probability that between 50 and 75 (inclusive) had fished?
c. If the 180 men selected for the interview were selected by the marketing department of a sporting-goods company based on information obtained from their mailing lists, what would you conclude about the reliability of their survey results?

Answers

Answer:

(a) The probability that fewer than 50 had fished is 0.0002.

(b) The probability that between 50 and 75 (inclusive) had fished is 0.6026.

Step-by-step explanation:

Let X = number of men who had fished during the year.

The probability of the random variable X is, p = 0.41.

A random sample of n = 180 men are selected.

The random variable X follows a Binomial distribution with parameters n = 180 and p = 0.41.

A Normal approximation to Binomial is applied when the following conditions are met,

np ≥ 10
n(1 - p) ≥ 10

Check:

$np=180*0.41=73.8>10\nn(1-p)=180* (1-0.41)=63.72>10$

Thus, the distribution of x can be approximated by a Normal distribution with:

Mean = $np=180*0.41=73.8$

Standard deviation = $√(np(1-p))=√(180*0.41*(1-0.41))=6.599$

(a)

Compute the probability that fewer than 50 had fished as follows:

$P(X<50)=P((X-\mu)/(\sigma)>(50-73.8)/(6.599))\n=P(Z<-3.61)\n=1-P(Z<3.61)\n=1-0.9998\n=0.0002$

Thus, the probability that fewer than 50 had fished is 0.0002.

(b)

Compute the probability that between 50 and 75 (inclusive) had fished as follows:

$P(50\leq X\leq 75)=P(49.5<X<75.5)\n=P((49.5-73.8)/(6.599)<(X-\mu)/(\sigma)<(75.5-73.8)/(6.599))\n=P(-3.68<Z<0.26)\n=P(Z<0.26)-P(Z<-3.68)\n=0.6026-0\n=0.6026$

Thus, the probability that between 50 and 75 (inclusive) had fished is 0.6026.

(c)

If the sample of 810 men are selected from mailing list then it is highly probable that the sample is not a representative of the true population, i.e. sports men.

Because the people interested in sports are less likely to be interested in fishing.

Thus, it could be concluded that the survey results are not reliable.

Find the distance between (-3,2) and (1,-3)