The lines of symmetry for the graph of equation 4x² + y² = 9 are the x-axis and the y-axis.
To determine the lines of symmetry of the graph of equation 4x² + y² = 9, we need to analyze the form of the equation.
The given equation represents an ellipse, as it contains terms for both x² and y².
Comparing this with the given equation 4x² + y² = 9, we can rewrite it as:
(2x)²/3² + y²/3² = 1
By comparing the equations, we can deduce that a² = 3² and b² = 3². This means that the major axis has a length of 2a = 2(3) = 6 and the minor axis has a length of 2b = 2(3) = 6.
Since the ellipse is symmetric with respect to both the x-axis and the y-axis, there are two lines of symmetry.
Learn more about ellipses here:
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Answer:
The length of the case is 24 cm and its width is 17cm.
Step-by-step explanation:
The Length of a standard jewel case is 7cm more than its width.
Let the length be represented by L and the width be represented by W, this means that:
L = 7 + W
The area of the rectangular top of the case is 408cm². The area od a rectangle is given as:
A = L * W
Since L = 7 + W:
A = (7 + W) * W = 7W + W²
The area is 408 cm², hence:
408 = 7W + W²
Solving this as a quadratic equation:
=> W² + 7W - 408 = 0
W² + 24W - 17W - 408 = 0
W(W + 24) - 17(W + 24) = 0
(W - 17) (W + 24) = 0
=> W = 17cm or -24 cm
Since width cannot be negative, the width of the case is 17 cm.
Hence, the length, L, is:
L = 7 + 17 = 24cm.
The length of the case is 24 cm and its width is 17cm.
What are the missing side lengths in PQR?
Please try to show your work
Answer: We are given Quadrilateral LMNO is reflected over a line.
Also given Quadrilateral LMNO is congruent Quadrilateral CDAB, that is
LMNO ≅ CDAB.
Note: Reflection over a line represents mirror images of the figures.
From the given image we can see
LM is congruent to CD.
ON is congruent to BA.
LO is congruent to BC.
MN is congruent to AD.
Therefore, DC segment corresponds to ML.
Hope i helped you out!