Please help with these math questions

Answers

Answer 1

Answer: 3) A
slope= (y2-y1)/(x2-x1)
(1--5)/(4-1)
6/3=2

4) 5/8
slope= (y2-y1)/(x2-x1)
(-1-4)/(-8-0)
-5/-8=5/8

5) 1/2
2x-4y=10
Change it into slope intercept form
-4y=-2x+10
y=1/2x-10/4
slope=m=1/2

Hope this helps.

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Last Saturday, Jay spent 6 hours playing games, studying and talking with his friends. he spent 2/5 of the time playing games and 1/2 of the time studying. How many minutes did he spend talking with his friends?
1/6+(-2/3)= a.-4/6b.1/2c.-1/2d.-5/6 plz only abitious and up

Please help me with this!!!

Answers

Answer:

(f•g)(2)=3 and (g•f)(6)=7

Step-by-step explanation:

look at the tables

where x is equal to both 2 and 7 is where you will find your answer

Hope this helps you!

I agree with the other person ;)

How many miles you can cover in 65 minutes

Answers

It depends on what type of transportation you would be using. If you were walking, it would be reeeaaaalllly slooowww. If a train, much faster!

It depends on how fast you are going. How fast?

What is the unit rate of 40 meters in 16 seconds?

Answers

40 meters in 60 seconds could be expressed as

$(40 meters)/(16 seconds)$

So, in order to get the unit rate, we divide the numerator and denominator by 16.

$(40)/(16) \n (40/16)/(16/16) \n (2.5)/(1) \n (2.5 meters)/(1 second)$

So, the unit rate is 2.5 meters per second (or every one second)

The unit rate us 2.5 meters each second to do this you could find the unit rate

Mario walked at a rate of 2/3 mile every 10 minutes. What was his rate in person hour? A.)4 B)6 2/3 C)9 D)15

Answers

$1~\text{h}=60~\mathrm{min}~~\Leftrightarrow~~\boxed{\begin{array}{c} 1\mathrm{~min}=(1)/(60)\mathrm{~h} \end{array}}$

Therefore,

$(2)/(3)~\frac{\mathrm{mile}}{10\mathrm{~min}}\n \n \n =(2)/(3)~\frac{\mathrm{mile}}{10\cdot ((1)/(60)~\mathrm{min})}\n \n \n =(2)/(3)~\frac{\mathrm{mile}}{(10)/(60)~\mathrm{min}}\n \n \n =(2)/(3)~\frac{\mathrm{mile}}{(1)/(6)~\mathrm{min}}\n \n \n =(2)/(3\cdot (1)/(6))~\frac{\mathrm{mile}}{\mathrm{min}}\n \n \n =(2)/(((3)/(6)))~\frac{\mathrm{mile}}{\mathrm{min}}\n \n \n =2\cdot (6)/(3)~\frac{\mathrm{mile}}{\mathrm{min}}\n \n \n =2\cdot 2~\frac{\mathrm{mile}}{\mathrm{min}}\n \n \n =4~\frac{\mathrm{miles}}{\mathrm{min}}$

A picture frame is 9 inches long and 6 inches wide. It can display a picture 6 inches long and 4 inches wide. What is the area of the picture frame?

Answers

Answer:

30 inches squared

Step-by-step explanation:

First, find the area of the entire frame using length times height. 9*6 is 54 inches squared. Then, find the area of the middle space the same way. 6*4 is 24 inches squared. Lastly, subtract the middle from the entire frame's area. 54-24 is 30 inches squared.

Answer:

30 in^2

Step-by-step explanation:

Frame

Length = 9

Width = 6

9 * 6 = 54in^2 (Multiply to get 54)

Picture

Length = 6

Width = 4

6*4 = 24in^2 ( Multiply to get 24 )

54 - 24 = 30in^2 ( Minus 24 from 54 to get 30)

Formula l*w

It's length times width NOT length times hight like the other person said

What is 2940 and 588 into fraction form

Answers

$(2940)/(588) = (588\cdot5)/(588) =5$

2940 divide by 588 equal to 5.