What is the velocity of a 500-kilogram elevator that has 4,000 joules of energy?
Answers
The velocity of a 500-kilogram elevator that has 4,000 joules of energy is 4m/s.
KINETIC ENERGY:
- The kinetic energy of a substance is its energy during motion. It can be calculated using the formula below:
K.E = ½m.v²
Where;
m = mass of the elevator (kg)
v = velocity of the elevator (m/s)
- According to this question, the energy of the 500kg elevator is given as 4,000 joules, hence, the velocity can be calculated as follows:
V = √K.E × 2/m
V = √4000 × 2/500
V = √8000/500
V = √16
V = 4m/s
- Therefore, the velocity of a 500-kilogram elevator that has 4,000 joules of energy is 4m/s.
Learn more: brainly.com/question/10703928?referrer=searchResults
Kinetic Energy = 1/2*mv², Where m is mass in kg, v is velocity in m/s
Energy is 4000 Joules, v = ?
mass, m = 500kg
1/2*mv² = E
1/2*500*v² = 4000
v² = (2*4000) / (500) Using a calculator
v² = 16 Taking square root
v = √16
v = 4
Velocity of object is 4 m/s.
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