A cylinder has a radius of 5 cm and a height of 4cm find the volume

Answers

Answer 1

Answer: The answer should be around 314.159. The formula is v=pi*r2*h. Plug in the numbers and its v=pi*25*4. That is 25*4 which is 100. Then *pi and it should be it.

Answer 2

Answer: It should be 314
Steps:
2
3.14 x 5 = 78.5
78.5 x 4

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What is 3 more than x
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What’s a general equation of an arithmetic series

Answers

The general equation of an arithmetic series is $a_(n) + a_(1) + (n - 1) d$

Hope this helps! :) from peachimin

Solve the equation log4(x + 20) = 3
x=
DONE

Answers

The value of x is 44.

Given

Equation; $\rm log4(x + 20) = 3$

The value of the x is determined by using the logarithmic properties following all the steps given below.

The value of x is;

$\rm log4(x + 20) = 3$

Taking log base 4 on both sides;

$\rm log4(x + 20) = 3\n\n(x+20) = 4^3\n\nx+20 = 4 * 4* 4\n\nx+20=64\n\nx=64-20\n\nx=44$

Hence, the value of x is 44.

To know more about Equation click the link given below.

brainly.com/question/7302008

Answer:

x = 44

Step-by-step explanation:

log4(x+20) = 3

4³ = x + 20

x + 20 = 64

x = 44

(Correctmeifiamwrong)

Sophia bought 3 yards of trim to put around a rectangular scarf. She wants the width of the scarf to be a whole number that is at least 6 inches and at most 12 inches. If she uses all the trim,wh Write your answers in inchesat are the possible dimensions of her scarf?

Answers

Answer:

The length of the scarf is at least 42 inches and at most 48 inches.

Step-by-step explanation:

We are given the following information:

Length of trim = 3 yards = 108 inches

The width of the scarf to be a whole number that is at least 6 inches and at most 12 inches.

Let w be the width of the scarf and l be the length of scarf.

Perimeter of scarf =

$\text{Permiter of rectangle} = 2(l+w)$

Then, we can write:

$6 \leq w \leq 12\n6+l \leq w+l \leq 12+l\n2(6+l) \leq 2(l+w) \leq 2(12+l)\n2(6+l) \leq \text{Perimeter of scarf}) \leq 2(12+l)\n2(6+l) \leq 108 \leq 2(12+l)\n\Rightarrow 2(6+l) \leq 108\n12 + 2l \leq 108\nl \leq 48\n\rightarrow 108 \leq 2(12+l)\n108 \leq 24 + 2l\nl \geq 42\n\Rightarrow 42 \leq l \leq 48$

The length of the scarf is at least 42 inches and at most 48 inches.

possible dimensions of the scarf are:
Width:6 inches Length:96inches
Width:12 inches Length:84 inches
Width:11inches Length: 86 inches
Width:10 inches Length: 88 inches
Width: 7 inches Length: 94 inches
Width: 8 inches Length: 92 inches
Width: 9 inches Length: 90 inches

NEED HELP ASAP A survey was conducted with high school students ineach grade to see how many prefer math or science.
Some of the data are shown below.
Which statement is true about the joint frequencies in
this table?
40
11 | 12 |
Total
O Twenty-three 9th graders and fifteen 11th graders
prefer math.
O Fourteen 11th graders prefer math and eight 10th
graders prefer science.
O Thirty-five 12th graders prefer math and nine 10th
graders prefer science.
Twenty-three 9th graders and thirty-two 12th
graders prefer math.
Math
18
90
Science 40
15
95
Total
63
26
29
67
185

Answers

Question:

a. Twenty-three ninth graders and fifteen eleventh graders prefer math.

b. Fourteen eleventh graders prefer math and eight tenth graders prefer English.

c. Thirty-five twelfth graders prefer math and nine tenth graders prefer English.

d. Twenty-three ninth graders and thirty-five twelfth graders prefer math.

e. Eighteen tenth graders prefer English and fourteen eleventh graders prefer math.

Answer:

Therefore, the correct options are;

b. and d.

Step-by-step explanation:

Here we have a table with blank boxes and totals from which we can fill the boxes;

For the 12th graders, we have a total of 67 pupils with 32 preferring English, therefore the number of the 12th graders that prefer math is 67 - 32 = 35 pupils

Similarly for the 11th graders we have total pupils = 29 with 15 preferring English, therefore the number of the 11th graders that prefer math is 29 - 15 = 14 pupils

Also for the 10th graders we have total pupils = 26 with 18 preferring math, therefore the number of the 11th graders that prefer English is 26 - 18 = 8 pupils

Finally for the 9th graders, we have a total of 63 pupils with 40 preferring English, therefore the number of the 9th graders that prefer math is 63 - 40 = 23 pupils

From the above, the correct option is

Answer:

b only

Step-by-step explanation:

Which is equivalent to 16 Superscript three-fourths x?RootIndex 4 StartRoot 16 EndRoot Superscript 3 x
RootIndex 4 x StartRoot 16 EndRoot cubed
RootIndex 3 StartRoot 16 EndRoot Superscript 4 x
RootIndex 3 x StartRoot 16 EndRoot Superscript 4

Answers

Answer:

Option A

Step-by-step explanation:

We want to find an expression that is equivalent to

${16}^{ (3)/(4)x }$

Recall that:

${a}^{ (m)/(n) } = \sqrt[n]{ {a}^(m) }$

We apply this property of exponents to rewrite our expression:

We set a=16, n=4 and m=3x

This implies that:

${16}^{ (3x)/(4) } = \sqrt[4]{ {16}^(3x) } = (\sqrt[4]{ {16} })^(3x)$

The first choice is correct.

Answer:

Step-by-step explanation:

edg review 2020

Describe the end behavior of the following function: F(x)=2x^4+x^3

Answers

The end behavior of the following function is that it starts high and ends high.

How do we make a graph of a function?

A graph contains data of which input maps to which output.

Analysis of this leads to the relations which were used to make it.

Suppose the considered function whose graph is function of x

Then the values of 'x' (also called input variable, or independent variable) are usually plotted on the horizontal axis, and output values function of x are plotted on the vertical axis.

We have been given a function of x as $2x^4 +x^3$

The graph of the given function starts high and ends high.

The function touches the origin in the middle of the line.

Hence, the end behavior of the following function is that it starts high and ends high.

Learn more about graphing functions here:

brainly.com/question/14455421

#SPJ5

Answer:

The graph of the function starts high and ends high.

Step-by-step explanation:

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~Please only answer if you know for sure~(State which answer goes to which question please) :)