Answer:
x = -7
Step-by-step explanation:
Please solve it from the picture below!!
The average height of the 10 tallest buildings in Los Angeles is than the average height of the tallest buildings in San Francisco. The mean absolute deviation for the 10 tallest buildings in San Francisco is
The answer:
Answer with explanation:
Average Height of tallest Building in San Francisco
Average Height of tallest Building in Los Angeles
→→Difference between Height of tallest Building in Los Angeles and Height of tallest Building in San Francisco
=233.9-197.8
=36.1
⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.
⇒Part B
Mean absolute deviation for the 10 tallest buildings in San Francisco
|260-197.8|=62.2
|237-197.8|=39.2
|212-197.8|=14.2
|197 -197.8|= 0.8
|184 -197.8|=13.8
|183-197.8|=14.8
|183-197.8|= 14.8
|175-197.8|=22.8
|174-197.8|=23.8
|173 -197.8|=24.8
Average of these numbers
Mean absolute deviation=23.12
Answer:
1st -36.1 meters or more
2nd -23.12
Step-by-step explanation:
Answer:
Step-by-step explanation:
The mean SAT score is , we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it ) is
Next they draw a random sample of n=70 students, and they got a mean score (denoted by ) of
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis
- The alternative would be then the opposite
The test statistic for this type of test takes the form
and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.
Answer:
The null hypothesis is that the SAT score is not significantly different for the course graduates.
Alternate hypothesis: there is a significant difference between the SAT score achieved by the course graduates as compared to the non-graduates.
Apply the t-test. The Test Statistic value comes out to be t = 1.738 and the p-value = 0.0844
Since the p-value is larger than 0.05, the evidence is weak and we fail to reject eh null hypothesis.
Hope that answers the question, have a great day!
Answer:
m = 6
Step-by-step explanation:
Step 1: Write out equation
-11 = -3m + 7
Step 2: Subtract 7 on both sides
-18 = -3m
Step 3: Divide both sides by -3
6 = m
Step 4: Rewrite
m = 6
Answer:
m = 6
Step-by-step explanation:
-11 = -3m + 7
Multiply -1 on both sides
11 = 3m - 7
11 + 7 = 3m
18 = 3m
18/3 = m
m = 6
Answer:
your answer is fifteen