The order of increasing atomic radius for the elements Li, Na, K, and Rb is Li
The arrangement of the following elements in increasing atomic radius: Li, Na, K, and Rb indicates that the atomic radius increases as we move down a group in the periodic table. This group of elements, Li, Na, K, and Rb, are all alkali metals and exhibit similar chemical behaviors. As the atomic number or Z increases, the atomic radius also increases. For example, Lithium (Li) has an atomic number of 3, Sodium (Na) 11, Potassium (K) 19, and Rubidium (Rb) 37. As we move down the group from Li to Rb, both Z and the atomic radius increase.
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When electricians get their license, they are only licensed to install parallel circuits. Most electricians aren't certified to install series circuits.
B.
Parallel circuits prevent electrons from flowing if part of the circuit is broken and therefore prevent fires. Series circuits cause more fires because electrons still flow.
C.
Electrons continue to flow in a parallel circuit even if part of the circuit is broken. In a series circuit, a break such as a burned out lightbulb would cause the current to stop in the whole room.
D.
Parallel circuits are much easier to wire and are required by the electrical code for housing construction in most communities. Series circuits are sometimes used with special approval.
Show, or explain, all of your work along with the final answer.
Q < Keq
Q > Keq
Q = Keq
Answer:
A. Q = Keq
B. Equilibrium quantities of reactants and products
C. Q > Keq
D. System will shift toward reactants
E. Overabundance of reactants
F. System will shift toward products
Here are all the answers :)
To fill in the table about equilibrium, if Q < Keq the reaction will move right (produce more products), if Q > Keq it will move left (produce more reactants), and if Q = Keq the system is at equilibrium with no net change.
To complete the first row in the table about a system at equilibrium, we need to fill in the missing information based on the reaction quotient (Q) and the equilibrium constant (Keq).
For a system at equilibrium, not only is Q = Keq, but also the change in Gibb's free energy (ΔG) is zero. This relationship can be represented as 0 ΔG° + RT ln K at equilibrium.