The electric potential difference is the electric potential energy per unit charge
Explanation:
First of all, we define the concept of electric potential. The electric potential is a measure of the gradient of the electric field at a certain point of the space. The electric potential at a distance from a positive charge of magnitude is given by
where k is the Coulomb's constant.
Now we can define the electric potential energy and the electric potential difference:
The electric potential energy is also defined as the work done on a charge q moved through a potential difference of . Consequently, the potential difference represents the work per unit charge done, i.e. the work done when moving a unitary charge through a potential difference .
Learn more about potential difference and current:
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Answer:
Mac’s Speed = 2.5 m/s
Tosh’s Speed = 4 m/s
Tosh moves 1.5 m/s faster than Mac.
Explanation:
Tosh starts from an initial position of 12m and in a span of 3 seconds, (1.00 seconds to 4.00 seconds) he moves 12 meters.
So his speed is distance / time
s = 12 / 3
s = 4 m/s
Mac starts from an initial position of 2m and in a span of 4 seconds, he traveled 10m (2.00m to 12.00m).
Speed = Distance / time
s = 10 / 4
s = 2.5 m/s
False
I feel like this is false because I know it is similar to that of a bar magnet. Right?
Central Forces.
c.
Central Powers.
b.
Allied Forces.
d.
Axis Powers.
Answer:
They collide, couple together, and roll away in the direction thatthe 2m/s car was rolling in.
Explanation:
We should start off with stating that the conservation of momentum is used here.
Momentum = mass * speed
Since, mass of both freight cars is the same, the speed determines which has more momentum.
Thus, the momentum of the 2 m/s freight car is twice that of the 1 m/s freight car.
The final speed is calculated as below:
mass * (velocity of first freight car) + mass * (velocity of second freight car) = (mass of both freight cars) * final velocity
(m * V1) + (m * V2) = (2m * V)
Let's substitute the velocities 1m/s for the first car, and - 2m/s for the second. (since the second is opposite in direction)
We get:
solving this we get:
V = - 0.5 m/s
Thus we can see that both cars will roll away in the direction that the 2 m/s car was going in. (because of the negative sign in the answer)
Both students do the same amount of work, but Ben delivers more power due to completing the work in a shorter time.
In this case, both Ben and Bonnie are lifting the same 50 kg barbell over their heads, but they are doing it at different rates. Bonnie lifts the barbell 10 times in one minute, which means she is doing the work over a longer period of time. Ben, on the other hand, lifts the barbell 10 times in 10 seconds, doing the work in a shorter amount of time.
The amount of work done is equal to the force exerted multiplied by the distance moved. Since the mass and distance are the same for both students, the work done is equal. However, power is defined as the rate at which work is done, which is calculated by dividing the work done by the time taken to do it. Since Ben completes the work in a shorter period of time, he delivers more power than Bonnie.
Therefore, Ben does the most work and delivers the most power.
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Answer:
Both of them
Explanation: