Using the formula A=l•w solve the following word problem. You have enough wallpaper to cover 240 square feet. If your walls are 8 feet high, what wall length can you paper? a. Wall length of 40 feet
b. Wall length of 30 feet
c. Wall length of 3 feet
d. Wall length of 16 feet

Answers

Answer 1
Answer: Hi there! The answer is B.

You have enough wallpaper to cover 240 square feet. If your walls are 8 feet high, what wall length can you paper?

First write down our data:
A = 240 square feet
l = 8 feet

Now we can fill in the formula
240 = 8 × w

Switch sides.
8 × w = 240

Divide both sides by 8.
w = 240 / 8 = 30

Therefore the answer is B.
Wall length of 30 feet
Answer 2
Answer:

Final answer:

Using the formula A=l•w to solve the wallpaper problem, where the area (A) is 240 square feet and the width (w) is the height of the walls (8 feet), we find that the wall length (length) that you can paper is 30 feet.

Explanation:

The subject of the word problem is finding the wall length you can cover with a given amount of wallpaper. In this case, the area of the wallpaper is 240 square feet, and the height of the walls is 8 feet.

The formula for the area of a rectangle is A=l•w, where A stands for area, l stands for length, and w stands for width. In this case, the 'width' is the height of the walls, which is 8 feet.

To find the length of the wall, we can rearrange the formula to l=A/w and substitute the given values. That means l=240/8, which gives us a wall length of 30 feet.

Therefore, the answer is b. Wall length of 30 feet.

Learn more about Area Calculation here:

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What is 0.55 as a fraction in it's simplest form?

Answers

0.55=(55)/(100)=(55:5)/(100:5)=(11)/(20)
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Write an equation in slope-intercept form of the line shown in the graph below.A. y = -2x + 1
B. y = -4x + 2
C. y = 4x + 2
D. y = 2x - 2

Answers

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Mauritius island is 2 km due south of its closest point along a straight coastline. Gibril is staying at a private room on the shore that is 6 km east of that point. Gibril is planning to go from the room to the island. Suppose Gibril runs at a rate of 8 kmph and swims at a rate of 3 kmph. How far should Gibril run before swimming to minimize the time it takes to reach the island?

Answers

Answer:

5.19 Km

Step-by-step explanation:

According To the Question,

Suppose he Runs Xkm before swimming to minimize the time it takes to reach the island .

So, he should swim \sqrt{2^(2)+(6-X)^(2)  } Km .

Now The Total Time is t = (X)/(8) + \frac{\sqrt{2^(2)+(6-X)^(2)  } }{3} .

t = (X)/(8) + \frac{\sqrt{X^(2)-12X+40  } }{3}

(dt)/(dX)=1/8 + 1/3 * 1/2 * \frac{2X-12}{\sqrt{X^(2)-12X+40 } }

(dt)/(dX)=1/8 + (1)/(3)  * \frac{X-6}{\sqrt{X^(2)-12X+40 } }

Now Put (dt)/(dX) = 0 , we get

1/8 + (1)/(3)  * \frac{X-6}{\sqrt{X^(2)-12X+40 } } = 0

(1)/(3)  * \frac{X-6}{\sqrt{X^(2)-12X+40 } } = - (1)/(8)

8(X-6)= -3 × {\sqrt{X^(2)-12X+40 }

square on both side,We get

64(X²-12X+36) = 9X² - 108X +360

55X² -660X + 1944 = 0

Apply Shri Dharacharya formula, To Find The Value of 'X'

X =[ - (-660) ±\sqrt{(-660)^(2)-4*55*1944 }  ] ÷ 2×55

X = (660±√7920) / 110

X= (660 - 89 ) / 110  ⇒ (Neglect '+' because it give 749/110 = 6.8 km Which is not possible )

X=571/110 ⇔ 5.19km he Should Run before swimming to minimize the time .

(For Diagram,Please Find In Attachment)

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Answers

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Five times x plus seven equals eighteen.

Hope this helps

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Answers


If the units digit is zero, then you have an even number ...
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Since it has two or more places,  5  and  10  are also factors.

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Answer:

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Answer:

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