x^2 -9
x+5
x-4
Answer:
Option 1
Step-by-step explanation:
We will find the solution for the expression in option 1
Hence, x=1 and x=-4 willl be the solution
Hence, will be in denominator.
Hence, Option 1 is correct
Option 2,3 and 4 are discarded.
Assuming peter made two transactions today at his bank. The sum -47.27 plus 598= 550.73 mean that:Peter withdraw $47.27 and deposited $598 , increasing his balance by $550.73.
Amount withdraw=$47.27
Amount deposited=$598
Availbale balance=$550.73
($598.00-$47.27)
Thus, Based on the above calculation assuming he withdraw $47.27 and deposited $598 his balance will increase by $550.73.
Learn more about debit and credit here:brainly.com/question/24164976
We want to get the resultant velocity and direction of an airplane given that we know the velocity of the airplane and the velocity of the wind.
We will get that the velocity is 70.7 mph and the direction is 85.8° north of east.
First, let's define north as the positive y-axis and east as the positive x-axis.
The airplane flies due north at 100mph, then the velocity of the airplane alone is:
V = (0mph, 100 mph)
The wind's velocity has a magnitude of 30mph at 80° south from east (or an angle of -80° in a general coordinate axis) then the components are:
Then the vector is:
V' = (5.2mph, -29.5 mph)
The resultant velocity is just the sum of these two vectors, so we have:
resultant velocity = (0mph, 100 mph) + (5.2mph, -29.5 mph)
= (5.2 mph, 70.5 mph)
The magnitude is:
M = √( (5.2 mph)^2 + ( 70.5 mph)^2) = 70.7 mph
And the direction is given by:
θ = Atan(70.5 mph/5.2 mph) = 85.8°
Meaning that the direction is 85.8° north of east.
If you want to learn more, you can read:
Answer:
velocity of the airiplaine is 104 m/s ( 73 degrees N of W)
Step-by-step explanation:
16×1+4(18÷2-9)
16×1+4(9-9)
16×1+4(0)
16×1
16
*Can someone show the work I have the answers
The zeros of a function are the points where the function cross the x-axis.
One other zero of is 2 + 3i.
The zero of is given as:
The above number is a complex number.
If a complex number a + bi is the zero of a function f(x), then the conjugate a - bi is also the zero of f(x).
This means that, one other zero of is 2 + 3i.
Read more about zeros of functions at:
Answer:
One other zero is 2+3i
Step-by-step explanation:
If 2-3i is a zero and all the coefficients of the polynomial function is real, then the conjugate of 2-3i is also a zero.
The conjugate of (a+b) is (a-b).
The conjugate of (a-b) is (a+b).
The conjugate of (2-3i) is (2+3i) so 2+3i is also a zero.
Ok so we have two zeros 2-3i and 2+3i.
This means that (x-(2-3i)) and (x-(2+3i)) are factors of the given polynomial.
I'm going to find the product of these factors (x-(2-3i)) and (x-(2+3i)).
(x-(2-3i))(x-(2+3i))
Foil!
First: x(x)=x^2
Outer: x*-(2+3i)=-x(2+3i)
Inner: -(2-3i)(x)=-x(2-3i)
Last: (2-3i)(2+3i)=4-9i^2 (You can just do first and last when multiplying conjugates)
---------------------------------Add together:
x^2 + -x(2+3i) + -x(2-3i) + (4-9i^2)
Simplifying:
x^2-2x-3ix-2x+3ix+4+9 (since i^2=-1)
x^2-4x+13 (since -3ix+3ix=0)
So x^2-4x+13 is a factor of the given polynomial.
I'm going to do long division to find another factor.
Hopefully we get a remainder of 0 because we are saying it is a factor of the given polynomial.
x^2+1
---------------------------------------
x^2-4x+13| x^4-4x^3+14x^2-4x+13
-( x^4-4x^3+ 13x^2)
------------------------------------------
x^2-4x+13
-(x^2-4x+13)
-----------------
0
So the other factor is x^2+1.
To find the zeros of x^2+1, you set x^2+1 to 0 and solve for x.
So the zeros are i, -i , 2-3i , 2+3i