your answer is 102,900 N
i just took the test
A = side length (L/2) ; distance between plates (d) ; dielectric current (k)
B = side length (L) ; distance between plates (d/2) ; dielectric current (4k)
C = side length (2L) ; distance between plates (d) ; dielectric current (2k)
D = side length (L) ; distance between plates (2d) ; dielectric current (2k)
The capacitance of the four capacitors, ranked from highest to lowest, is B = C (they both have equal capacitance), followed by D, and then A.
The capacitance of a parallel-plate capacitor is given by C = εA/d, where ε is the permittivity of the dielectric material (which is equal to the product of the vacuum permittivity and the relative permittivity or dielectric constant k), A is the area of one of the plates, and d is the separation between the plates.
Applying this formula to the four capacitors and simplifying:
When ranked from highest to lowest capacitance, the order will be B = C > D > A.
#SPJ12
B. increase circuit power
.C. allow current flow between its plates.
D. store electric charges.
Answer:
D. Stores electric charges