28 ft
-----------
15 ft
square feet
Submit
Answer:
⇒minimum payment is 2% of her balance or 10 bucks...whichever is greater...
her balance is 360
2% of 360 =
0.02(360) = 7.20
$ 10 is greater then 7.20 so ur answer is $ 10
pls mark as brainlesttttt
Answer:
Her minimum payment would be $10.
Step-by-step explanation:
To find this, first find 2% of her statement. We can do this by multiplying the amount by the percentage.
$360 * 2% = $7.20
Now, since this is less than the given minimum, she pays the $10 minimum.
The slope of a line that is perpendicular to a line whose equation is −2y = 3x + 7 is
Solution:
Given that we have to find the slope of the line that is perpendicular to a line whose equation is −2y = 3x + 7
The slope intercept form is given as:
y = mx + c
Where "m" is the slope of line and "c" is the y - intercept
Given equation is:
On comparing the above equation with slope intercept form,
We know that product of slope of a line and slope of line perpendicular to it is -1
Therefore,
Thus slope of line that is perpendicular to given line is
Answer:
1) For
A) Domain=
B) Range=
C) y-intercept = 0
D) Asymptote= No asymptote
2) For
A) Domain=Domain=
B) Range=
C) y-intercept = None
D) Vertical Asymptote: x=0
Step-by-step explanation:
Given : and
Refer the graph attached.
1) In equation (1)
→The domain is the set of all possible values in which function is defined.
y=5x is a linear polynomial defined on all real numbers.
Domain=
→Range is the set of all values that function takes.
It also include all real numbers.
Range=
→y-intercept- Value of y at the point where the line crosses the y axis.
put x=0 in equation y=5x we get, y=0
Therefore, y-intercept = 0 (We can see in the graph also)
→An asymptote is a line that a curve approaches, but never touches.
Asymptote= No asymptote
2) Now in equation (2)
Domain=
because log function is not defined in negative.
Range=
y-intercept - None
Vertical Asymptote: x=0
1)
A) Domain= (-∞, ∞) for all x
B) Range= (-∞, ∞) for all y
C) y-intercept = 0
D) Asymptote= No asymptote
2)
A) Domain=(0, ∞) for all x > 0
B) Range= (-∞, ∞) for all y
C) y-intercept = None
D) Vertical Asymptote: x=0
Here, we have,
Function 1: y = 5x
Domain: The domain of this function is all real numbers because there are no restrictions on the values that x can take.
Range: The range of this function is also all real numbers because for every value of x, we can find a corresponding y value by multiplying it by 5.
Y-intercept: To find the y-intercept, we set x = 0 and solve for y. Substituting x = 0 into the equation, we get y = 5(0) = 0. Therefore, the y-intercept is (0, 0).
Asymptotes: There are no asymptotes in this linear function.
Function 2: y = log₅x
Domain: The domain of this function is all positive real numbers because the logarithm function is only defined for positive values of x.
Range: The range of this function is all real numbers because the logarithm function can produce any real number output.
Y-intercept: To find the y-intercept, we set x = 1 and solve for y. Substituting x = 1 into the equation, we get y = log₅(1) = 0. Therefore, the y-intercept is (0, 0).
Asymptotes: The logarithmic function has a vertical asymptote at x = 0 because the logarithm is undefined for x ≤ 0. Additionally, there is no horizontal asymptote.
When plotting these functions on the same set of axes, we will observe that the graph of y = 5x is a straight line passing through the origin (0, 0) with a slope of 5.
The graph of y = log₅x will appear as a curve that starts at the point (1, 0) and approaches the vertical asymptote x = 0 as x approaches zero.
The two graphs will intersect at the point (1, 0) because log₅1 = 0.
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