Answer : Option D) Proton and Neutron.
Explanation : The part of the atom that carries a positive charge is the proton, and the part that carries a neutral charge is the neutron.
A proton is a small subatomic particle, denoted by symbol , with a positive electric charge of +1 e elementary charge and a mass which is slightly less than that of a neutron. It is located at the center o atomic nucleus along with neutron. The number of protons are equal to the number of electrons of that atom but are in opposite charges.
A neutron is a subatomic particle of an atom which is of the same mass as that of proton but without an electric charge, it is present in all atomic nuclei except those of ordinary hydrogen. It is also located at the center of an atomic nucleus.
Answer:
The correct answer is CO2 diffuses passively out of the cell.
Explanation:
Carbon dioxide is one of the end product of cellular metabolism.CO2 is produced as waste material inside the body after cellular respiration.
Carbon dioxide is transported out from the body by passive diffusion process which helps the CO2 gas to move along the concentration gradient from high concentration region(body) to the low concentration region(atmosphere).
Thus CO2 ia being eliminated from our body.
B.they increase the concentration of reactants
C.they decrease the concentration of products
D. They act as reactants
Answer:
D) They act as reactants
Explanation:
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Answer: Aluminum is ideal for aircraft manufacture because it's lightweight and strong.
Explanation:
C) Ba(ClO4)2. D) Ba(NO3)2
is insoluble in water.
Further Explanation:
Solubility rules
These help in predicting whether the given compound is soluble or insoluble in nature. Some of the solubility rules are as follows:
1. Group 1A compounds are soluble in nature.
2. All the common compounds of ammonium ion and all acetates, chlorides, nitrates, bromides, iodides, and perchlorates are soluble in nature. But the ions whose chlorides, bromides, and iodides are not soluble are , , and .
3. All common fluorides, except for and group 2A fluorides are soluble. Also, all sulfates except , , , and are soluble.
4. All common metal hydroxides except , , and hydroxides of group 1A and that of transition metals are insoluble in nature.
5. All carbonates are insoluble in nature, except for sodium, potassium and ammonium.
6. Salts having ions like , or are generally soluble except those of , and .
7. Group 1A and group 2A perchlorates are soluble in nature.
8. All sulfates of metals are soluble, except for lead, mercury (I), barium, and calcium sulfates.
9. The salts having nitrate ions are soluble in nature.
According to the solubility rules, only carbonates of sodium, potassium and ammonium are soluble in nature. So barium carbonate is insoluble in nature. But chlorides, nitrates and perchlorates of barium are soluble in water. Therefore option A is the correct answer.
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Answer details:
Grade: Senior School
Chapter: Chemical reaction and equation
Subject: Chemistry
Keywords: barium, water, insoluble, solubility rules, soluble, insoluble, water, BaCO3.
BaCO₃ is generally considered insoluble in water. Carbonates are often insoluble, except for some alkali metals and ammonium carbonates. Therefore, option A is correct.
The solubility of salt depends on its nature and the interactions between its ions and water molecules. In this case, determine the solubility of each salt by considering the common solubility rules.
BaCl₂ is soluble in water. Chlorides (Cl-) are mostly soluble except for a few exceptions, such as silver chloride, lead chloride, and mercury(I) chloride.
Ba(ClO₄)₂ is soluble in water. Perchlorates (ClO4-) are typically soluble.
Ba(NO₃)₂ is soluble in water. Nitrates (NO3-) are mostly soluble.
Based on the solubility rules, the salt that is insoluble in water is BaCO₃ (barium carbonate).
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For example,
"Which of the following molecules is expected to have one or more unpaired electrons? Check all that apply.
O2-
F2+
N22-
O22-"
Any help would be appreciated. ...?
To determine unpaired electrons, look at the valence electrons in an ion's molecule, accounting for extra or absent electrons due to the ion's charge. For instance, O2- and F2+ have one unpaired electron, but N22- is not a valid ion, and O22- electrons are all paired.
To determine if a molecular ion will have one or more unpaired electrons, we need to look at the number of valence electrons in the molecule and take into account any extra or absent electrons due to the charge of the ion.
For example, O2- has 12 + 1 = 13 valence electrons (6 from each oxygen atom and 1 extra due to the negative charge). It requires 14 for all the electrons to be paired (2 in each oxygen's inner shell and 4 bonds or lone pairs in the outer shell), thus there is one unpaired electron in O2-.
However, in F2+, there are only 13 electrons because one electron is lost due to the positive charge. Like oxygen, fluorine also prefers to have 7 electrons in its outer shell, so there are also unpaired electrons in F2+.
N22- doesn’t exist because nitrogen normally forms triple bond and doesn’t need or want to take extra electrons, so this molecular ion is not valid.
O22- has 14 + 2 = 16 valence electrons and this total number of valence electrons is an even number, which indicates all the electrons are paired.
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