the sum of three numbers is 161 the second number is six times the first and the third is 5 more than the second find the numbers

Answers

Answer 1

Answer: x+y+z=161 . y=7+x . z=5x. x+x+7+5x=161 . x=22 y=x+7=29 z=5x=110

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Carrie pick 23 brooches of flowers From her garden each bunch had the same number of flowers after she gave 46 flowers away she had 138 left how many flowers were in each bunch.

Answers

according to question

total flowers = 23x
23x - 46 = 138
23x = 138 + 46 = 184
x = 8

8 flower in each bunch

hope this helps you ...

There were 6 flowers in each bunch

138÷23=6

The Parks Department wants to put a sidewalk diagonally across a square park. The perimeter of the park is 8 miles. a. What is the width of the park?

What will the length of the sidewalk be? Round your answer to the nearest tenth

Answers

The width of the part is 2 miles, this is because the park is square which means all sides are equal. This is computed by dividing 8 miles by 4 sides of the park which give us the answer of 2 miles. The length of the side walk is 2.8 miles. This computed using Pythagorean Theorem, which states that the hypotenuse is solve by the square root of the square of both sides. Then will give us the answer of 2.8 miles.

a radio station requires DJs to play 2 commercials for every 10 songs tgey play.what is the unit rate o songs to commercial?

Answers

5 songs (for every 1 commercial)

Evaluate -x2 +x–1 forx=-1

Answers

Answer:

-3

Step-by-step explanation:

-x^2 +x–1

Let x = -1

- (-1)^2 + (-1) -1

- 1 -1 -1

-3

Answer:

Step-by-step explanation:

the equation after plugging in "x" is

-(-1)*(2)+(-1)-1

then after multiplication it is

2-1-1

this becomes 0

In this diagram, what is ac?

Answers

Answer:

AC = 10 units .

Step-by-step explanation:

Given : Triangle ABC.

To find : What is AC.

Solution : We have given Triangle ABC.

Triangle BCD is right angle triangle .

By the Pythagorean theorem :

$(BC)^(2) = (BD)^(2) + (CD)^(2)$ .

Plug the values .

$(17)^(2) = (BD)^(2) + (8)^(2)$ .

289 = $(BD)^(2) + 64$ .

On subtractin g 64 from both sides.

289 - 64 = $(BD)^(2)$ .

225 = $(BD)^(2)$ .

Taking square root .

BD = $√(225)$ .

BD 15 units .

AB = AD+ BD

21 = AD + 15

AD = 21 -15

AD = 6 units .

Now , Triangle ACD is right angle triangle .

$(AC)^(2) = (6)^(2) + (8)^(2)$ .

$(AC)^(2) = 36 +64$ .

$(AC)^(2) = 100$ .

Taking square root

AC = 10 units .

Therefore, AC = 10 units .

$\sqrt{17 {}^(2) { - 8}^(2) } = 15 \n 21 - 15 = 6 \n \sqrt{8 { }^(2) } + √(6 ) {}^(2) = 10 \n c.10$

In the situation, simple interest is calculated yearly. How much interest was earned? Drag and drop the answer into the box. Principal: $8000; Time: 4 years; Interest rate: 12%; Interest: ?