What is the difference x +5/ x +2 - x + 1/x ^2 + 2x?

Answers

Answer 1
Answer: ANSWER
The difference is,

\frac{ {x}^(2) + 4x - 1}{ {x}^(2) + 2x}

EXPLANATION

To find the difference, we just have to simplify the expression.

The given expression is

(x + 5)/(x + 2) - \frac{(x + 1)}{ {x}^(2) + 2x}

We factor the denominator of the second fraction to get,

=(x + 5)/(x + 2) - ((x + 1))/( x( x+ 2))

We can now see clearly that the LCM is

x(x + 2)

We collect LCM to get,

=(x(x + 5) - (x + 1))/( x( x+ 2))
We now expand the bracket to obtain,

=\frac{ {x}^(2) + 5x - x - 1}{ {x}^(2) + 2x}

This gives us,

=\frac{ {x}^(2) + 4x - 1}{ {x}^(2) + 2x}
Answer 2
Answer: The difference will be given by:
(x +5)/ (x +2) - (x + 1)/(x ^2 + 2x)
=
(x +5)/ (x +2) - (x + 1)/[x (x + 2)]
the LCM is x(x+2)
thus the difference will be:
[x(x+5)-(x+1)]/(x (x + 2))
=[x^2+5x-x-1]/[x(x+2)]
=(x^2-4x-1)/[x(x+2)]

Answer:(x^2-4x-1)/[x(x+2)]

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2. Use the binomial theorem to expand the expression. (а — 2b)^5

Answers

Answer:

(a-2b)^(5)=-32b^(5)+80ab^(4)-80a^(2)b^(3)+40a^(3)b^(2)-10a^(4)b+a^(5)

Step-by-step explanation:

The binomial expansion is given by:

(x+y)^(n)=_(0)^(n)\textrm{C}x^{^(0)}y^(n)+_(1)^(n-1)\textrm{C}x^(1)y^(n-1)+...+_(n)^(n)\textrm{C}x^(n)y^(0)

In our case we have

x=a\ny=-2b\nn=5

Thus using the given terms in the binomial expansion we get

(a-2b)^(5)=_(0)^(5)\textrm{C}a^(0)(-2b)^(5)+_(1)^(5)\textrm{C}a^{^(1)}(-2b)^(4)+{_(2)^(5)\textrm{C}}a^(2)(-2b)^(3)+_(3)^(5)\textrm{C}a^(3)(-2b)^(2)+_(4)^(5)\textrm{C}a^(4)(-2b)^(1)+_(5)^(5)\textrm{C}a^(5)(-2b)^(0)

Upon solving we get

(a-2b)^(5)=-32b^(5)+5* a*16b^(4)+10* a^(2) * (-8b^(3))+10* a^(3)* 4b^(2)+5* a^(4)* (-2b)+a^(5)\n\n(a-2b)^(5)=-32b^(5)+80ab^(4)-80a^(2)b^(3)+40a^(3)b^(2)-10a^(4)b+a^(5)

The ratio of green apples to red apples at a grocery store is 2 to 3. There are 78 red apples at the grocery store. What is the total number of apples at the store?

Answers

Answer:

52

Step-by-step explanation:

78 divided by 3 is 26

26 times 2 is 52

Give the domain and range of the relation (1, -8),(-7, 8),(-3,7),(-3,-5)

Answers

Answer:

Domain = {-3, 1, -7}

Range = {-8, 8, 7, -5}

Step-by-step explanation:

Find the zeros of the function
k(x) = -5x² - 125
The zeros of k are x= □ and x= □​

Answers

Answer:

x = ±5i

General Formulas and Concepts:

Pre-Alg

  • Order of Operations: BPEMDAS

Alg II

  • √-1 is imaginary number i

Step-by-step explanation:

Step 1: Define function

k(x) = -5x² - 125

Step 2: Find roots

  1. Set function equal to 0:                    0 = -5x² - 125
  2. Factor out -5:                                     0 = -5(x² + 25)
  3. Divide both sides by -5:                    0 = x² + 25
  4. Subtract 25 on both sides:               -25 = x²
  5. Rewrite:                                              x² = -25
  6. Square root both sides:                     x = ±√-25
  7. Rewrite:                                              x = √-1 · ±√25
  8. Evaluate:                                             x = ±5i

A 1-kg model airplane has 12.5 joules of kinetic energy and 98 joules of gravitational potential energy. What is its speed? What is its height?

Answers

The formula for the kinetic energy is:

Ke = 0.5mv^2

Where ke is the kinetic enrgy

M is the mass

V is the velocity

Ke = 0.5mv^2

12.5 = 0.5(1) v^2

Solve for v

V = 5 m/s

Potential energy, pe = mgh

Where m is mass

G is accelearation due to gravity 9.8 m/s2

H is the height

98 = (1)(9.8) h

H = 10 m

                       

Find the surface area of thetriangular prism.
6 m
8 m
7 m
10 m
[?] sqm

Answers

Answer:

the answer is 10

Step-by-step explanation: