Answer:
1. Use the distance formula to measure the lengths of the sides.
3. Use the slope to check whether sides are perpendicular and form right angles.
5. Use the slope to check whether the diagonals are perpendicular to each.
Step-by-step explanation:
We know that, the distance formula given by
,
gives the length of the line joined by and .
Now, after using this formula, if:
1. The length of the opposite sides are equal, then the quadrilateral could be a rectangle or a parallelogram.
2. The length of all sides are equal, then the quadrilateral could be a square or a rhombus.
So, this gives us option 'Use the distance formula to measure the lengths of the sides' is correct.
Now, we use slope to find the angles i.e. If:
1. The product of two slopes is -1, then the lines are perpendicular and so, forms right angle between them.
2. The slope of two lines are equal, then the lines are parallel.
So, this gives us that the option 'Use the slope to check whether sides are perpendicular and form right angles' is correct.
Since, some quadrilaterals have the property that the diagonals are perpendicular bisector of each other.
So, the option 'Use the slope to check whether the diagonals are perpendicular to each other' is also correct.
Hence, option 1, 3 and 5 are correct.
Using a limited selection from among the options, a quadrilateral, or
triangle can be classified into one of the eleven classes.
The correct options are;
Reasons:
The classification of triangles are;
Right triangles; Having two legs that are perpendicular
Isosceles triangles; Having two sides equal
Equilateral triangles; Having all sides equal
Scalene triangle; Have all sides of different dimensions
Classification of quadrilaterals are;
Kite, rhombus, rectangle, parallelogram, square, trapezoid, isosceles trapezoid
Use the distance formula to measure the lengths of the sides;
Use the slope to determine whether the sides are perpendicular and form right angles;
Use the slope to check whether the diagonals are perpendicular;
Learn more about slope, distance formula, triangles and quadrilaterals here:
Answer:
y(t)= 11/3 e^(-t) - 5/2 e^(-2t) -1/6 e^(-4t)
Step-by-step explanation:
We know that , so we have
By using the method of partial fraction we have:
Now we have:
Using linearity of inverse transform we get:
Using the inverse transforms
we have:
Express your answer in terms of pi.
Answer:
6π ft
Step-by-step explanation:
PA=3ft
Then just double it to get your answer.
Answer:
7 + 35v
Step-by-step explanation:
7 × 1 + 5v × 7
7 + 35v
Hope this helps and have a nice life d:
Answer:
C(60) = 2.7*10⁻⁴
t = 1870.72 s
Step-by-step explanation:
Let x(t) be the amount of chlorine in the pool at time t. Then the concentration of chlorine is
C(t) = 3*10⁻⁴*x(t).
The input rate is 6*(0.001/100) = 6*10⁻⁵.
The output rate is 6*C(t) = 6*(3*10⁻⁴*x(t)) = 18*10⁻⁴*x(t)
The initial condition is x(0) = C(0)*10⁴/3 = (0.03/100)*10⁴/3 = 1.
The problem is to find C(60) in percents and to find t such that 3*10⁻⁴*x(t) = 0.002/100.
Remember, 1 h = 60 minutes. The initial value problem is
dx/dt= 6*10⁻⁵ - 18*10⁻⁴x = - 6* 10⁻⁴*(3x - 10⁻¹) x(0) = 1.
The equation is separable. It can be rewritten as dx/(3x - 10⁻¹) = -6*10⁻⁴dt.
The integration of both sides gives us
Ln |3x - 0.1| / 3 = -6*10⁻⁴*t + C or |3x - 0.1| = e∧(3C)*e∧(-18*10⁻⁴t).
Therefore, 3x - 0.1 = C₁*e∧(-18*10⁻⁴t).
Plug in the initial condition t = 0, x = 1 to obtain C₁ = 2.9.
Thus the solution to the IVP is
x(t) = (1/3)(2.9*e∧(-18*10⁻⁴t)+0.1)
then
C(t) = 3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴t)+0.1)
If t = 60
We have
C(60) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴*60)+0.1) = 2.7*10⁻⁴
Now, we obtain t such that 3*10⁻⁴*x(t) = 2*10⁻⁵
3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 2*10⁻⁵
t = 1870.72 s
Answer:
Step-by-step explanation:
→We can write 9 as And 100 can be written as
→Now we take the square root of the two we get
→ Then We get the Answer
Answer:
3/10
Step-by-step explanation:
Answer:
1/4x^2 + x =-1/4
=−2±√3
Answer:
1/4x^2 + x =-1/4
=−2±√3
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Step-by-step explanation: