Answer:
b
Step-by-step explanation:
you have to find the common denominator or turn it into a decimal
For this case we must indicate the result of the following expression:
We must build a quotient that, when multiplied by the divisor, eliminates the terms of the dividend until it reaches the remainder.
It must be fulfilled that:
Dividend = Quotient * Divider + Remainder
Answer:
See the attached image
Option A
Answer: Choice A
Step-by-step explanation:
Answer:
(a) 3x -y = 7
(b) x +3y = 29
Step-by-step explanation:
(a) The standard form of the given line is ...
3x -y = 5
The parallel line will have a constant on the right that makes it go through (5, 8), so it will be ...
3x -y = 3(5) -(8)
3x -y = 7
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(b) The perpendicular line will have coefficients for x and y swapped and one of them negated. Again, the constant is chosen to make it go through (5, 8).
x + 3y = (5) +3(8)
x + 3y = 29
Answer:
74°
Step-by-step explanation:
b + 16°= 90°
b = 74°
the steps to the equation
f(x) = x3 + 4x2 − x − 4
f(x) = x3 + 3x2 − 4x − 12
f(x) = x3 + 2x2 − 4x − 8
Answer:
Step-by-step explanation:
From the graph, the x-intercepts are;
These are root of the polynomial function represented by the given graph.
By the remainder theorem;
According to the factor theorem, if is a factor of , then
This implies that;
are factors of the required function.
Hence;
We expand using difference of two squares to obtain;
We expand using the distributive property to get;
Rewrite in standard form to obtain;
Answer:
Choice A: f(x) = x^3 + x^2 − 4x − 4
Step-by-step explanation:
Here's a great and simple answer.
Ok first we need to take the x intercepts to solve.
If we look at the graph we see the x ints are -2,+1 and +2.
To solve we need to put them into factor form
= (x-2) (x+2) and (x+1)
Simplify: (x-2) (x+2) = (x^2-4) and (x+1)
Now we take (x^2-4) and (x+1) and multiply them to find our answer
(x^2-4) (x+1)
= x^2(x) and x^2(1) = x^3 and x^2.
now the other: -4(x) and -4(+1) = -4x and -4
We have nothing common here so we just join them
= x^3 + x^2 - 4x - 4, and that is the same as choice A.